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Shkiper50 [21]
3 years ago
11

Express 35 1/3 in simplest radical form.

Mathematics
1 answer:
Georgia [21]3 years ago
5 0
3√35-simplest radical form
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The Thompson Family decides to plant a total of 180 plants in order to prepare for a larger
Licemer1 [7]

Answer: 54 berry plants

Step-by-step explanation:

From the sample there are:

Lettuce = 12

Tomatoes = 6

Peppers = 3

Berries = 9

The total is: = 12 + 6 + 3 + 9 = 30 plants

Berries comprise of:

= 9/30

= 3/10 of the plants

If they want to plant a total of 180, the number of berrie plants needed is:

= 3/10 * 180

= 54 berry plants

8 0
3 years ago
Can y’all help me on question 27?!
dimulka [17.4K]

Answer: C. 78

Step-by-step explanation: Good luck! :D

There are 12 inches in a foot, there are 6 feet. 6 x 12 = 72

1/2 of a foot is 6 inches. 72 + 6 = 78!

8 0
2 years ago
Un cable guía de 600 pies esta sujeto a la parte superior de una torre de comunicaciones. Si el cable forma un ángulo de 65° con
natita [175]

Answer:

La torre tiene 543.78 pies de altura.

Step-by-step explanation:

Podemos pensar en esta situación como si fuera un triángulo rectángulo, donde el cable es la hipotenusa y la torre es uno de los catetos. (Abajo se puede ver un dibujo de esta situación).

Nosotros queremos encontrar el valor de H, que es el cateto opuesto al ángulo conocido de 65°.

Entonces simplemente podemos usar la relación:

Sin(θ) = (cateto opuesto)/(hipotenusa)

donde:

cateto opuesto = H

θ = 65°

hipotenusa = 600 ft

sin(65°)  = H/600ft

sin(65°)*600ft = H = 543.78 ft

La torre tiene 543.78 pies de altura.

8 0
2 years ago
Killian went to the movies with his mother, 2 brothers, and 2 sisters. The theater had choices of 2 different types of soda and
bazaltina [42]
Yeshhh it is possible !
7 0
3 years ago
A set of weights includes a 10 lb barbell and 8 pairs of weight plates. Each pairof plates weighs 20lbs. If x pairs of plates ar
Leni [432]

It is given that the weight of the barbel is given by:

f(x)=20x+10

It says that there are eight pair of weights so x can take values from 0 to 8 and f(x) can take the values as follows:

\begin{gathered} x=0,f(x)=10 \\ x=1,f(x)=30 \\ x=2,f(x)=50 \\ x=3,f(x)=70 \\ x=4,f(x)=90 \\ x=5,f(x)=110 \\ x=6,f(x)=130 \\ x=7,f(x)=150 \\ x=8,f(x)=170 \end{gathered}

So the range is:

\mleft\lbrace10,30,50,70,90,110,130,150,170\mright\rbrace

Option B is correct.

4 0
1 year ago
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