The answer is refracts parallel to the axis of the lens
100. A centimeter is a 100th of a meter.
Note that the density of mercury is
(i) 13545 kg/m^3 at 20 deg.C
(ii) 13472 kg/m^3 at 50 deg, C
For a given mass, M kg, by using the volume at 20 deg. C, obtain
M = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg .
Let V m^3 = volume at 50 deg. C
Then
(13472 kg/m^3)*(V m^3) = 27.09 kg
V = 27.09/13472 = 0.002010837 m^3
Answer:
The closest answer is A. 0.002010812 m^3
Answer:
b is the answer the third law
Explanation:
Answer:
124.86 V
Explanation:
We have to first calculate the voltage drop across the copper wire. The copper wire has a length of 358 ft
1 ft = 0.3048 m
358 ft = 109.12 m
The diameter of 2 AWG copper wire (d) = 6.544 mm = 0.006544 m
The area of the wire = πd²/4 = (π × 6.544²)/4 = 33.6 mm²
Resistivity of wire (ρ) = 0.0171 Ω.mm²/m
The resistance of the wire =
The voltage drop across wire = current * resistance = 6.1 A * 0.056 ohm = 0.34 V
The voltage at end = 125.2 - 0.34 = 124.86 V