Question

An optical fiber uses one glass clad with another glass. What is the critical angle? (Assume the glass in the fiber has an index of refraction of 1.69, and the glass in the cladding has an index of refraction of 1.50.)

Answer 1

Answer:

The critical angle is $\theta _c = 62.57^o$

Explanation:

From the question we are told that

    The  index of refraction of the glass in the fiber is $n_f = 1.69$

     The index of refraction of the glass in the cladding is $n_c = 1.50$

The critical angle is mathematically evaluated as

       $\theta_c = sin^{-1}[\frac{n_c }{n_f } ]$

substituting values

       $\theta_c = sin^{-1}[\frac{1.50 }{1.69 } ]$

       $\theta _c = 62.57^o$