Answer:
Given sequence is not a geometric progression and there will be no common ration for this sequence.
Step-by-step explanation:
Need to determine common ration for the following geometric sequence
32, 8, 2, 12, ...
In given geometric sequence
a1 = 32, a2=8, a3=2, a4=12 ……….
Common ratio = 



Since
so we can say that given sequence is not a geometric progression and there will no no common ration for this sequence.
Step-by-step explanation:
Let's represent the number of mochas bought with the variable
, and the number of lattes bought with the variable
.
Since there are
students, the total number of mochas and lattes bought must be
. This can be represented with the following equation:

We can also set up another equation based on the total amount spent on the coffe:

If we rearrange the first equation, we can solve for
:

If we substitute this into the second equation, we can solve for
:





Subtituting this back into the original equation, we can solve for
:



Therefore, 9 mochas and 14 lattes were bought.
Answer:
120 blocks total
Step-by-step explanation:
All of the little cubes have side length 2" Thus, the 11" height of the box cannot be used entirely: we waste the top 1" because the five layers of little cubes reach only to 10" from the bottom.
Start at the bottom of the box. The dimensions of the bottom are 12" by 8". Along the longer side we can lay 6 blocks (which add up to 12" and are 2" wide. We can add 3 more such rows to fill the available 8" width of the box bottom. That's 6*4, or 24 blocks.
We can add 4 more 6 block by 4 block layers before we have the maximum 5 layers stacked in the box.
5 layers times 24 blocks per layer comes to 120 blocks total.
2 boys 4 girls Add those together then divid And Then Use diffences And theres ur Awnser
Answer:
The distance between the astronomers and the moon was
meters.
Step-by-step explanation:
We have that the speed is the distance divided by the time, so:

In this problem, we have that:
The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that
.
If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?
We have that
m/s.
We have to find d. So:



![7.56*10^{8]](https://tex.z-dn.net/?f=7.56%2A10%5E%7B8%5D)
The distance between the astronomers and the moon was
meters.