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3 years ago

7

If 3 times a certain number is increased by 4 the result is 28. What is the number? If xis "the number," which of the following

equations could be used to solve for the number? 3 x + 4 = 28 KOE 3 X= 4 + 28 30 x + 4) = 28

1 answer:

Dimas [21]3 years ago

8 0

Answer:

The first one (3x+4=28)

Step-by-step explanation:

3x+4=28

28-4=24

24/3=8

x=8

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sammy [17]

Step-by-step explanation:

The last step is a little wrong. Lemme show you:

x(x + 2) + (x + 2)

Imagine there is an invisible '1' infront of (x + 2) like this:

= x(x + 2) + 1(x + 2)

Now we can combine the like terms together:

= (x + 1)(x + 2)

This is the correct factorization.

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Answer:

y=y(.11y+8)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

Factor -8x^3-2x^2-12x-3

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$-8x^3-2x^2-12x-3\\\\=-2x^2(4x+1)-3(4x+1)\\\\=(4x+1)(-2x^2-3)\\\\=\boxed{-(4x+1)(2x^2+3)}$

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3 years ago

$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent

photoshop1234 [79]

$\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
\\
\text{we know that the amount after t year when compounded is given by}\\
\\
A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
\\
\text{here P is the principal amoount, so }P=7000,\\
\\
\text{r is the interest rate, }r=11\%=0.11\\
\\
\text{n is the number of times in a year, here semiannulay, so }n=2,\\
\\
\text{and t is the time, so }t=21\\
\\
\text{so the amount after 21 years is}$

$A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
\\
\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
\\
\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
\\
\Rightarrow A\approx 66328.68$

So the amount after 21 years is: $66328.68

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3 years ago