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3 years ago

5√27-2√48-5√3-√(3-2√3)2

Mathematics

1 answer:

gregori [183]3 years ago

7 0

Answer:

4√3

Step-by-step explanation:

5√27-2√48-5√3-(√3-2√3)2

= 5√(3x9)-2√(3x16)-5√3-2√3+4√3

= 5(3)√3-2(4)√3-5√3-2√3+4√3

= 15√3-8√3-5√3-2√3+4√3

= 4√3

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RSB [31]

Answer:

Identity is true

Step-by-step explanation:

$\frac{cos\theta+1}{tan^2\theta}=\frac{cos\theta}{sec\theta-1}$

$(cos\theta+1)(sec\theta-1)=(tan^2\theta)(cos\theta)$

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$(cos\theta)(\frac{1}{cos\theta})-cos\theta+sec\theta-1=\frac{sin^2\theta}{cos\theta}$

$1-cos\theta+sec\theta-1=\frac{sin^2\theta}{cos\theta}$

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$sec\theta-cos\theta=\frac{sin^2\theta}{cos\theta}$

$\frac{1}{cos\theta}-cos\theta=\frac{sin^2\theta}{cos\theta}$

$\frac{1}{cos\theta}-\frac{cos^2\theta}{cos\theta}=\frac{sin^2\theta}{cos\theta}$

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Therefore, the identity is true.

Helpful tips:

Pythagorean Identity: $sin^2\theta+cos^2\theta=1\\cos^2\theta=1-sin^2\theta\\sin^2\theta=1-cos^2\theta$

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Olegator [25]

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Step-by-step explanation:

Hi there !

if f(x) = 2x + 7 and f(x) = -1 =>

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Answer:

Step-by-step explanation:

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