3x^2 - 4x + 2 = 0 <br> how many solutions does the equation above have?

kirza4 [7]

2x+3y=17 --- 1
3x+6y=30 --- 2
x+2y=10
x=10-2y --- 3
Sub 3 into 1,
2(10-2y)+3y=17
20-4y+3y-17=0
3-y=0
y=3 --- 4
Sub 4 into 3,
x=10-2(3)
x=4

Therefore, Answer is (4,3).

4 0

3 years ago

Read 2 more answers

Solve for the value of X in 9^x+4(3^x+1)+27=0

worty [1.4K]

Answer:

No solutions

Step-by-step explanation:

$9^x + 4(3^x + 1) + 27 = 0\\3^{2x} + 4 \cdot 3^x + 31 = 0$

Substitute 3^x with t and we get.

$t^2 + 4t + 31 = 0\\\triangle = 16 - 4 \cdot 31 = -108 < 0 => t_{12} \notin R => x \notin R$

3 0

3 years ago

Approximately 68% of films are rated R. If 720 films were recently rated, how many were rated R?

zloy xaker [14]

Answer:

Approximately 490 films were rated R.

Step-by-step explanation:

Total films recently rated is 720. About 68% of the films were rated R. Thus, 68% of 720 is calculated below.

$68\% \: of \: 720 \: films$

$= \frac{68}{100} \times 720$

$= 0.68 \times 720$

$= 489.6$

$= 490 \: films \: (approximated)$

Therefore, if 720 films were recently rated, 68% of films rated R is about 490 films.

3 0

3 years ago

There are blue, red and white counters in a bag in the ratio 16 3 2 There are 112 more blue counters than white counters. How ma

olga nikolaevna [1]

We will have 16 white counters in the bag.

Given that there are blue, red, and white counters in a bag in the ratio 16:3:2, the total number of balls will be:

Total = 16 + 3 + 2
Total = 21

If there are <em>112 more blue counters than white counters</em>, then;

number of blues = number of white + 112

16x = 2x + 112

14x = 112

x = 8

Number of white counters = 2x = 2(8) = 16

Therefore we will have 16 white counters in the bag.

Learn more on ratios here: brainly.com/question/2914376

5 0

2 years ago

Choose the graph which represents the solution to the inequality:<br> 3x + 8 ≥ 11

Mashutka [201]

The solution of the inequality is x ≥ 1.

Solution:

Given inequality:

$3 x+8 \geq 11$

To find the solution of the inequality:

$3 x+8 \geq 11$

Subtract 8 from both sides.

$3 x+8-8 \geq 11-8$

$3 x \geq 3$

Divide by 3 on both sides.

$$\frac{3 x}{3} \geq \frac{3}{3}$

On simplifying this, we get

$x \geq 1$

The solution of the inequality is x ≥ 1.

The graph of the solution is attached below.

8 0

2 years ago

3x^2 - 4x + 2 = 0 how many solutions does the equation above have?