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2 years ago

There are 216 blueberries in 6 baskets. What is the unit rate of blueberries per basket?

Mathematics

2 answers:

Brrunno [24]2 years ago

7 0

36 blueberries per basket

Leviafan [203]2 years ago

6 0

Answer:

it might be 36

Step-by-step explanation:

you're going to want to say 216/6 so it will definitely be an integer of some positive value

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f(x) = -4x^2+12x-9f(x)=−4x 2 +12x−9f, left parenthesis, x, right parenthesis, equals, minus, 4, x, squared, plus, 12, x, minus,

Olin [163]

Answer:

The graph has only one x-intercept

Step-by-step explanation:

we have

$f(x)=-4x^2+12x-9$

we know that

The discriminant of a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$D=b^{2}-4ac$

in this problem we have

$f(x)=-4x^2+12x-9$

$a=-4\\b=12\\c=-9$

substitute

$D=12^{2}-4(-4)(-9)$

$D=144-144$

$D=0$

The discriminant is zero

That means ----> The quadratic equation has one real solution

The graph has only one x-intercept

3 0

3 years ago

Help please show work

BARSIC [14]

Answer:

ok first you do the small one. 13 * 5 * 1/2 = 32.5 then you do 35 *1/2=17.5. you then divide 32.5/17.5=1.86

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

5 0

3 years ago

The perimeter of a pentagon is the sum of the lengths of its sides. In a regular pentagon, all sides have the same length.

Oksanka [162]

Since a pentagon has 5 sides, you would divide the perimeter by the number of sides.

641.5/5 = 128.3cm

Therefore, the length of one side of the pentagon is 128.3cm.

7 0

3 years ago

4. Solve the system using substitution.

Yuri [45]

Answer:

Step-by-step explanation:

-3+2=-1 and (9)- 8=1

3 0

2 years ago