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s344n2d4d5 [400]

3 years ago

13

Please help! I need this to pass. If you are trying to get points please just chose a different question and don't mess with min

e. I am in a state of trouble and I just need a helping hand.

1 answer:

Hunter-Best [27]3 years ago

3 0

Given:

Radius of the cylinder = 2 cm

Height of the cylinder = 3 cm

To find:

The surface area of the cylinder.

Solution:

The surface area of a cylinder is:

$A=2\pi rh+2\pi r^2$

Where, r is the radius and h is the height of the cylinder.

Putting $r=2,h=3,\pi = 3.14$ , we get

$A=2(3.14)(2)(3)+2(3.14)(2)^2$

$A=37.68+25.12$

$A=62.8$

Therefore, the surface area of the cylinder is 62.8 square cm.

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Write the equation of a line with the slope of 2, which contains the point

Crazy boy [7]

Answer:

y=2x-16

Step-by-step explanation:

So since we have a point and the slope, we can use the point-slope equation to find our equation of a line

y - y₁ = m(x - x₁)

Here our (x₁, y₁) point is (4, -8) and our m is 2

Plugging in these values to our equation gives us:

y - (-8) = 2(x - (4)) → distributing the negative to the -8 gives y + 8 = 2(x - 4) → distributing the 2 to the (x - 4) gives y + 8 = 2x - 8 → and finally subtracting the 8 from both sides gives our equation of a line y = 2x - 16

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4 years ago

1,298.713832<br>+2.475,147,963

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1412.188832

Step-by-step explanation:

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3 years ago

Whats the distance between coordinates (-6,8) and (-6,-3)

insens350 [35]

Answer:

there away from eachother for 5 spaces.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Determine the region of the xy-plane where the solution of the DE would have a unique solution passing through the point (x0,y0)

Virty [35]

Answer:

given equation,

$(9-y^2)\dfrac{dy}{dx}= x^4\\(9-y^2)dy = x^4 dx\\\int (9-y^2)dy =\int x^4 dx\\9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+C$

so,

the given point from where the region is passing through is (x₀, y₀)

hence, the unique equation comes out to be

$9y_0 -\dfrac{y_0^3}{3} = \dfrac{x_0^5}{5}+C$

$C = 9y_0 -\dfrac{y_0^3}{3}-\dfrac{x_0^5}{5}$

hence unique equation,

$9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+ 9y_0 -\dfrac{y_0^3}{3}-\dfrac{x_0^5}{5}$

6 0

3 years ago

The first term of a geometric sequence is 6 and the fourth term is 384. What is the sum of the first 10 terms of the correspondi

aleksandrvk [35]

Answer:

2097150

Step-by-step explanation:

<u>GIVEN :-</u>

First term of G.P. = 6
Forth term of G.P. = 384

<u>TO FIND :-</u>

Sum of first 10 terms of the G.P.

<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>

<em>Geometric Progression :-</em>

It's a sequence in which the successive terms have same ratio.

General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]

Sum of 'n' terms of a G.P. ⇒ $\frac{a(r^n - 1)}{r-1}$ .

<em>[NOTE :- </em> $\frac{a(1-r^n)}{1-r}$ can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>

<u>SOLUTION :-</u>

Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.

⇒ a = 6

It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-

$=> ar^3 = 384$

$=> 6r^3 = 384$

Divide both the sides by 6.

$=> \frac{6r^3}{6} = \frac{384}{6}$

$=> r^3 = 64$

$=> r = \sqrt[3]{64} = 4$

Sum of first 10 terms $= \frac{6(4^{10}-1)}{4 - 1}$

$= \frac{6(1048576 - 1)}{3}$

$= 2 \times 1048575$

$= 2097150$

6 0

3 years ago