Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
Divide both sides by 49/36 to get y by itself:
Simplify this fraction:
Now you have your answer:
Answer: she is jogging 2.25 i think
Step-by-step explanation:
im sorry im not sure i just divided 135 by 60 but i dont think its right:(
Answer: 164 students passed and 41 students failed.
Step-by-step explanation:
Let the number of students be x
x students failed, but 4 times the failed students passed.
So 4x students passed and x students failed.
4x + x = 205
5x = 205
x = 205/5
x = 41
41 times 4 is 164 and 41 times 1 is 41.
So 164 students passed and 41 students failed
