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Neko [114]
3 years ago
11

If cos θ - sin θ = √2 sin θ, then prove that cos θ + sin θ = √2 cos θ.

Mathematics
1 answer:
belka [17]3 years ago
5 0

Step-by-step explanation:

cos θ - sin θ = √2 sin θ

cos θ + sin θ = √2 sin θ + 2sin θ

cos θ + sin θ = √2(sin θ + √2sin θ)

cos θ + sin θ = √2 cos θ. (Proven)

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Divide 35 by 12. Input your answer as a reduced fraction
Mars2501 [29]

Answer: =2 2 /3

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Converting to a mixed number using long division with remainders for 8 ÷ 3.

8÷3=2R2

Therefore:

83=223

3 0
2 years ago
The solution of a system of linear equations is where the two lines intersect....
olchik [2.2K]

Answer:

True

Step-by-step explanation:

The place where lines intersect is where the x and y values match up.

Just like this, if the lines do not intersect, there's no solution.

If the lines seem to be one line, there is all real number solutions.

Hope this helped!

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2 years ago
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What is the slope-intercept form of the function described by this table?
r-ruslan [8.4K]
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The intercept is where x=0. Since we know that (1,2) is a point, we subtract 5 from 2 to get the intercept. Therefore, the intercept is -3

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4 0
3 years ago
Consider the expression below
brilliants [131]
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4 0
3 years ago
choose the equation in point slope form for the line that is perpendicular to the given line and passing through the given point
alexdok [17]

We want to determine the equation in point slope form for the line that is perpendicular to the given line and passing through the point (5.6) .

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y=\frac{2}{3}x+9,(5,6)

We know that for two lines to be perpendicular, the product of their slopes should be -1.

Therefore, the slope of the perpendicular should be;

m=-\frac{1}{(\frac{2}{3})}=-\frac{3}{2}

The second condition is that the line must pass through the point (5,6) , to do thid, we write the equation of the line in point slope form which is;

y-y_1=m(x-x_{1_{}})

Inserting all values, we have,

y-6=.-\frac{3}{2}(x-5)

That is the final answer.

6 0
1 year ago
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