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o-na [289]
2 years ago
12

It takes five days to repair 1250 meters of road. At this rate, how long will it take to repair 8 km of road?

Mathematics
1 answer:
rewona [7]2 years ago
3 0
32 days bcz 1250 meters took 120 hours (120 hrs=5 days) so 8000 m will take: 8000x120/1250= 768 hrs
782 hrs/24= 32 days
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WILL MARK BRAINLIEST
ValentinkaMS [17]

Answer:

The answer to your question is:

x = 13

x + 10 = 23

5x - 42 = 23

Step-by-step explanation:

Data

angle 1 = x + 10

angle 2 = 5x - 42

They are vertical angles so, they measure the same.

                     x + 10 = 5x -42

                    x - 5x = -42 - 10

                       - 4x = -52

                           x = -52/-4

                           x = 13

angle 1 = x + 10 = 13 + 10 = 23

angle 2 = 5x - 42 = 5(13) -42 =  65 -42 = 23

8 0
3 years ago
What is mesure of <MEF
Harrizon [31]
I think you forgot to add a photo
6 0
3 years ago
PLEASE help no scam or ill report
dezoksy [38]

Answer:

These opposite angles are called  Vertical Angles.

5 0
2 years ago
Two last help with math please and thanks!
12345 [234]
1st problem:
Use the Pythagorean theorem:
a^2+b^2=c^2
49+361=c^2
c^2=410
c=20.24
The answer is 20m

2nd problem:
First calculate the height using the Pythagorean theorem:
a^2+b^2=c^2
20^2+b^2=625     (i got 20 {radius} by half-ing the base edge length)
400+b^2=625
b^2=225
b=15

Next, solve for the volume:
V=a^2*h/3
V=40^2*15/3
V=1600*5
V=8000

The answer is the second choice or B.

5 0
3 years ago
Read 2 more answers
A group of engineers is building a parabolic satellite dish whose shape will be formed by rotating the curve y=ax 2 about the y-
Setler79 [48]

Answer:

a = \frac{1}{2}. Surface Area = \frac{4}{3}ft^{2}. and area of the Dish = \frac{4}{3}ft^{2}+pi4^{2} = \frac{4}{3}ft^{2}+50.27=51.6ft^{2}

Step-by-step explanation:

(1) Constant. y(x) = ax^{2} that is the curve that we need to rotate around the y axis to get the parabola with diameter of 8 feet and 2 meter depth that statement is translated in mathematics as x = -4 to 4 and y = 0 to 2.

y max = 2, x max = 4 setting up a equation with a unknown gives

2=a4 and  a = \frac{1}{2}.

so we have now.

y(x) = \frac{1}{2}x^{2} (Done with solving for a Constant).

(2) Surface Area.

Setting Up surface integral.

(i) range in x = 0 to 4.

(ii) range in y = 0 to 2.

integral is.

Integral(0-2)[{integral[(0-4)\frac{1}{32}x^{2}]}]dy

Evaluating this integral gives. \frac{4}{3}ft^{2}.

and area is surface area + area of the circle with 8ft diameter.

= \frac{4}{3}ft^{2}+pi4^{2} = \frac{4}{3}ft^{2}+50.27=51.6ft^{2}...

Note the Difference between area and aurface area.!

6 0
3 years ago
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