Question

Graph f(x)= -(x-2)²+4">

Answer 1

Answer: See the graph attached.

Step-by-step explanation:

The standard form of a quadratic function is:

$f(x)=a(x-h)+k$

Where (h,k) is the vertex of the parabola.

If $a$ is negative, then the parabola opens down.

Then, for the function:

$f(x)=-(x-2)^2+4$

You can identify:

$h=2\\k=4$

Then the  vertex of the parabola is at (2,4)

Note that $a=-1$, therefore the parabola opens down.

Find the intersection with the x-axis. Substitute $f(x)=0$ and solve for x:

$0=-(x-2)^2+4\\0=x^2-4x\\0=x(x-4)\\\\x_1=0\\x_2=4$

Knowing that the vertex is at (2,4), the parabola opens down and it intersects the x-axis at x=0 and x=4, you can graph the function, as you observe in the figure attached.