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2 years ago

⅛ ÷ 2 Please help! I need to remember this!

Mathematics

2 answers:

Anon25 [30]2 years ago

8 0

Answer:

$\frac{1}{16}$

Step-by-step explanation:

For this type of problem, I do KCF (Keep, Change Flip)

⅛ ÷ 2

Keep the fraction (⅛)

Change the sign to a multiplication (×)

Flip the "2" to its reciprocal ( $\frac{1}{2}$ )

Now we have a new expression

$\frac{1}{8}$ × $\frac{1}{2}$

Now we multiply from across

The numerator × Numerator

The denominator × denominator

1 × 1 = 1

8 × 2 = 16

Our answer will be....

$\frac{1}{16}$

Hope this helped!

Have a supercalifragilisticexpialidocious day!

Naya [18.7K]2 years ago

6 0

Answer:

1/16

Step-by-step explanation:

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---------------------

A quadratic equation has the following format:

$y = ax^2 + bx + c$

It's roots are:

$y = 0$

Thus

$ax^2 + bx + c = 0$

They are given by:

$\Delta = b^{2} - 4ac$

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

The discriminant is $\Delta$ .

If it is positive, $-b + \sqrt{\Delta} \neq -b - \sqrt{\Delta}$ , and thus, the quadratic equation has two real distinct roots, and it crosses the x-axis twice.

If it is zero, $-b + \sqrt{\Delta} = -b - \sqrt{\Delta}$ , and thus, it has one real root, and touching the x-axis.

If it is negative, $\sqrt{\Delta}$ is a complex number, and thus, the roots will be complex and will not touch the x-axis.

A similar problem is given at brainly.com/question/19776811

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