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Nostrana [21]
4 years ago
9

In the expression “a-10”, what is the 10?

Mathematics
1 answer:
k0ka [10]4 years ago
5 0

Answer:

it means to the power of so a is youre variable and the ten is the power to so you would multiply it 10 times so a^10 is to the tenth power

Step-by-step explanation:

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Determine LaShawn's average speed in meters per hour
abruzzese [7]
His average speed per minute is 1,448 meters per minute, and there are 60 minutes in a single hour. You would multiply 1,448 by 60 to get the answer of 86,880 meters per hour.
6 0
3 years ago
What is the value of 4 in the number 546 210
Komok [63]

Answer:

4 has value of 10,000 which ten thousand place value.

Step-by-step explanation:

Given number 546210

We have to find the value of 4 in given number 546210.

We write the given number in value form as ,

546210 = 5×100000 + 4× 10000 + 6 ×1000 + 2×100 + 10  

in words it is written as

Here, 4 has value of 10,000 which ten thousand place value.  

3 0
4 years ago
Read 2 more answers
Order from Greatest to Least 2.35, 2.05, 2.03, 2.30, 2.53, 2.5
nika2105 [10]

2.53, 2.5 , 2.35, 2.30, 2.05, 2.03

5 0
3 years ago
-7/10+7/15+1/-20+-9/10+11/15+11/-20 <br> what is the answer please help me .....!!!!
Nat2105 [25]

Answer:

-1

Step-by-step explanation:

-7/10+7/15+1/-20+-9/10+11/15+11/-20

= -7/10 + -9/10 + 7/15 + 11/15 + 1/-20 + 11/-20

= -16/10 + 18/15 + 12/-20

= -8/5 + 6/5 + -3/5

= (-8+6-3)/5

= -5/5

= -1

7 0
3 years ago
The parallelogram ABCD below, line AC is a diagonal, the measure of angle ABC is 40, and the measure of angle ACD is 57. What is
Strike441 [17]

Answer:

Using properties of parallelogram and angle sum property of a triangle in the figure as shown below in the attachment

In parallelogram ABCD, AC is a diagonal.

Given:  \angle ABC = 40^{\circ} and \angle ACD= 57^{\circ}

As, we know that opposite angles in parallelogram are equal.

therefore,

\angle ABC =\angle ADC= 40^{\circ}

Now, in ΔADC

Sum of the measures of angles in a triangle is 180 degree.

\angle ACD+ \angle ADC+\angle DAC =180^{\circ}

Substituting the values of \angle ADC= 40^{\circ} and  \angle ACD= 57^{\circ}  we have;

57^{\circ}+40^{\circ}+\angle DAC =180^{\circ}

or

97^{\circ}+\angle DAC =180^{\circ}

Subtract 97^{\circ} from both sides we get

\angle DAC =180 -97 =83^{\circ}

Therefore, the measure of angle CAD is 83^{\circ}.









3 0
3 years ago
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