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sukhopar [10]
2 years ago
12

3x+4y=8 please solve for Y

Mathematics
1 answer:
baherus [9]2 years ago
4 0

Answer:

(8-3x)/4

Step-by-step explanation:

3x+4y=8

4y=8-3x

y=(8-3x)/4

So the answer is (8-3x)/4

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The box plot below represents some data set. What is the interquartile range (IQR) of
vesna_86 [32]

Answer:

I think the IQR is 100

Step-by-step explanation:

You would have to find the first and third quartiles first. After that you would subtract the third quartile by the first to get the IQR

6 0
2 years ago
Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos
Kamila [148]

Answer:

3

Step-by-step explanation:

The fractions are: \frac{1}{5} and \frac{2}{3}. Let's take a look at the denominators: 5 and 3. The LCD of 5 and 3 is 15. 5x3=15, 3x5=15. So now we would multiply the denominators to make them the same number like this: \frac{5}{15} and \frac{10}{15}. Remember that if you multiply the denominator by a certain number, you must multiply the numerator by the same number as well. For example, in \frac{2}{3}, we multiply 3 by 5 and 2 by 5. Same number. Now with that out of the way, let's work on the equation: \frac{1}{5} + \frac{2}{3}. We know it is the same as \frac{5}{15} and \frac{10}{15}. So now all we do is add the numerators together: 5+10=15 or \frac{15}{15}. Now we have to reduce the fraction. \frac{15}{15} can be reduced to 3 by dividing 15 by 5=3. The final fraction is \frac{3}{3} or can be simply put as 3 since 3/3 is a whole number. That's it - you're done!

7 0
2 years ago
PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
  • \tan{\theta} = \pm \frac{\sqrt{2}}{4}

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0
1 year ago
How do i solve this question
frozen [14]
\bf \begin{cases}&#10;h(x)=(f\circ g)(x)\\&#10;h(x)=\sqrt{x+5}\\&#10;f(x)=\sqrt{x+2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus&#10;\\\\\\&#10;\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore&#10;\\\\\\&#10;\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\&#10;g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}
8 0
3 years ago
What is the surface area?<br> 8 mm<br> 10 mm<br> 5 mm<br> Explain how you arrived at your answer.
lesya692 [45]

Answer:

400 mm

Step-by-step explanation:

8 * 10 = 80

80 * 5 = 400

400 mm

7 0
2 years ago
Read 2 more answers
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