Answer:
- -2/a³ m/s
- -2 m/s
- -1/4 m/s
- -2/27 m/s
Step-by-step explanation:
The velocity is the derivative of position:
v = ds/dt = (d/dt)(t^-2) = -2t^-3
For t=a, the velocity is
-2a^-3 = -2/a³ . . . . meters per second
For t=1, the velocity is ...
-2·1³ = -2 . . . . meters per second
For t=2, the velocity is ...
-2·2^-3 = -2/8 = -1/4 . . . . meters per second
For t=3, the velocity is ...
-2·3^-3 = -2/27 . . . . meters per second
Answer:
the slope is 
Step-by-step explanation:
Notice that you are given two points to use for the slope calculation:
So we use the formula for the slope of a line given two points:
System of Linear Equations entered :
[1] 5x - 6y = 7
[2] 6x - 7y = 8
Graphic Representation of the Equations :
-6y + 5x = 7 -7y + 6x = 8
Solve equation [2] for the variable x
[2] 6x = 7y + 8
[2] x = 7y/6 + 4/3
// Plug this in for variable x in equation [1]
[1] 5•(7y/6+4/3) - 6y = 7
[1] - y/6 = 1/3
[1] - y = 2
// Solve equation [1] for the variable y
[1] y = - 2
// By now we know this much :
x = 7y/6+4/3
y = -2
// Use the y value to solve for x
x = (7/6)(-2)+4/3 = -1
Step-by-step explanation:
Explanation:
The trick is to know about the basic idea of sequences and series and also knowing how i cycles.
The powers of i will result in either: i, −1, −i, or 1.
We can regroup i+i2+i3+⋯+i258+i259 into these categories.
We know that i=i5=i9 and so on. The same goes for the other powers of i.
So:
i+i2+i3+⋯+i258+i259
=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)
We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.
=65(i)+65(i2)+65(i3)+64(i4)
From here on out, it's pretty simple. You just evaluate the expression:
=65(i)+65(−1)+65(−i)+64(1)
=65i−65−65i+64
=−65+64
=−1
So,
i+i2+i3+⋯+i258+i259=-1
Answer:
<h2>
</h2>
Step-by-step explanation:
w = yh - 2yc³
First of all factorize y out of the expression on the right side of the equation
That's
w = y( h - 2c³)
Next divide both sides by (h - 2c³) to make y stand alone
We have
<h3>
</h3>
We have the final answer as
<h3>
</h3>
Hope this helps you
