Answer:
Area of Triangle QRP = 3![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Step-by-step explanation:
According to Question , We have a circle With Centre 'O' & Area 48
.
Area Of Circle = 48![\pi](https://tex.z-dn.net/?f=%5Cpi)
![\pi](https://tex.z-dn.net/?f=%5Cpi)
= 48![\pi](https://tex.z-dn.net/?f=%5Cpi)
r = ![\sqrt{48}](https://tex.z-dn.net/?f=%5Csqrt%7B48%7D)
Now We Have Two Points Given On Circle Q & R , P Is Circumcentre Of Triangle QRO .
Thus A Circle Can Also Be Formed with Centre P . ( See attachment For Diagram )
Now The Diameter of Circle With Centre P = Radius Of Circle with Centre O
so Radius Of Circle With Centre P(
) = ![\frac{\sqrt{48}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B48%7D%7D%7B2%7D)
Now We Have To Find Area Of Equilateral Triangle .
A =
A= ![\frac{\sqrt{3} }{4} * \frac{\sqrt{48} }{2}*\frac{\sqrt{48} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%20%2A%20%5Cfrac%7B%5Csqrt%7B48%7D%20%7D%7B2%7D%2A%5Cfrac%7B%5Csqrt%7B48%7D%20%7D%7B2%7D)
The Area Of PQR is = 3
For Diagram , Please Find In Attachment
Hi there!
Let's use x for the width because we know the width is only 1. Next, we'll use 5x for the length because the length is 5 times the width. Now, we can set up an equation to solve for x.
WORK:
x * 5x = 1620
5x^2 = 1620
x^2 = 324
x = 18
ANSWER:
The width of the rectangle is 18 centimeters
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
54/60
Step-by-step explanation:
I hope this helps
a=-8 fraction of 7
Answer:
34 years
Step-by-step explanation:
f = s + 28 Eq. 1
f+8 = 3(s+8) Eq. 2
f = father age
s = son age
replacing Eq. 1 on Eq. 2
(s+28) + 8 = 3(s+8)
s + 36 = 3*s + 3*8
s + 36 = 3s + 24
36 - 24 = 3s - s
12 = 2s
12/2 = s
s = 6
from the Eq. 1
f = 6 + 28
f = 34
Check
from the Eq. 2
34+8 = 3(6+8)
42 = 3*14