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lesya692 [45]
3 years ago
14

If the circle has a 6 in radius, what is the area of this circle?

Mathematics
2 answers:
ivolga24 [154]3 years ago
6 0

Answer:

6

Step-by-step explanation:

nexus9112 [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Area= 113.09734 round it up to 113.1

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Question 24 Multiple Choice Worth 1 points)
hammer [34]

Given:

The system of equations is:

Line A: y=x-4

Line B: y=3x+4

To find:

The solution of given system of equations.

Solution:

We have,

y=x-4              ...(i)

y=3x+4           ...(ii)

Equating (i) and (ii), we get

x-4=3x+4

-4-4=3x-x

-8=2x

Divide both sides by 2.

-4=x

Substituting x=-4 in (i), we get

y=-4-4

y=-8

The solution of system of equations is (-4,-8).

Now verify the solution by substituting x=-4, y=-8 in the given equations.

-8=-4-4

-8=-8

This statement is true.

Similarly,

-8=3(-4)+4

-8=-12+4

-8=-8

This statement is also true.

Therefore, (-4,-8) is a solution of the given system of equations, because the point satisfies both equations. Hence, the correct option is C.

8 0
3 years ago
A card is randomly drawn from a standard $52$-card deck. An ace of hearts wins the grand prize; any other ace or heart wins a sm
gogolik [260]

Answer:

3/52

Step-by-step explanation:

4 0
3 years ago
What is the local minimum value of the function? (Round answer to the nearest hundredth) g(x)=x^4-5x^2+4
Serhud [2]
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0

Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).

4 0
4 years ago
Read 2 more answers
What would be the volume of the cone that has the same measurement as the cylinder above in the pic
fomenos

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Volume of cone will be ~

\fbox \colorbox{black}{ \colorbox{white}{volume} \:  \:  \:   \:   \: \colorbox{white}{=}  \:  \:   \:   + \colorbox{white}{462 \: cm³ }}

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's find the volume of cone with ~

  • radius (r) = 7 cm

  • height (h) = 9 cm

And as we know, volume of cone is equal to ~

  • \dfrac{1}{3}\pi  {r}^{2} h

now, let's plug in the values and find the volume ~

  • \dfrac{1}{ \cancel{3}  }\times  \dfrac{22}{\cancel{7}}  \times \cancel{7 }\times 7 \times \cancel{9}

  • 1 \times 22 \times 7 \times 3

  • 462 \:  \:  {cm}^{3}

Volume of cone is 462 cm³ = 462 ml

7 0
3 years ago
Lisa spends part of her year as a member of a gym. She then finds a better deal at another gym
Tema [17]
I’m having trouble understanding this question.?
5 0
3 years ago
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