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Novay_Z [31]
3 years ago
8

Question 24 Multiple Choice Worth 1 points)

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Given:

The system of equations is:

Line A: y=x-4

Line B: y=3x+4

To find:

The solution of given system of equations.

Solution:

We have,

y=x-4              ...(i)

y=3x+4           ...(ii)

Equating (i) and (ii), we get

x-4=3x+4

-4-4=3x-x

-8=2x

Divide both sides by 2.

-4=x

Substituting x=-4 in (i), we get

y=-4-4

y=-8

The solution of system of equations is (-4,-8).

Now verify the solution by substituting x=-4, y=-8 in the given equations.

-8=-4-4

-8=-8

This statement is true.

Similarly,

-8=3(-4)+4

-8=-12+4

-8=-8

This statement is also true.

Therefore, (-4,-8) is a solution of the given system of equations, because the point satisfies both equations. Hence, the correct option is C.

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x^{\frac{1}{\frac{-3}{6} }}

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x^{\frac{6}{-3} }

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x^{-2}. Some professors might accept this as simplest form, but others might ask you to get rid of the negative.

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The data in which table represents a linear function that has a slope of zero? I can’t figure it out
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Answer:

A

Step-by-step explanation:

Think about it.

y = (0)x + b

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y = b

therefore Y equals a single number regardless of the x value.

This behavior is shown in table A.

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3 years ago
Need help! Does anyone know how to do this type of math? (It's geometry)
mart [117]

Answer:

71

Step-by-step explanation:

<u>refer</u><u> </u><u>the</u><u> attachment</u>

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that <u>tangents </u><u>which</u><u> </u><u>meet </u><u>at</u><u> the</u><u> </u><u>same</u><u> </u><u>point</u><u> </u><u>are </u><u>equal</u><u> </u><u> </u>that is being said

  • FA=AI=17
  • CH=CG=2.5

since \rm BA=FA+FB and it's given that FA and BA are 17 and 29 FB should be

  • \rm 29=17+FB

therefore,

  • FB=29-17=\boxed{12}

once again by two tangent theorem we acquire:

  • FB=BH=\boxed{12}

As BC=BH+CH,BC is

  • 12+2.5
  • \boxed{14.5}

likewise,AD=AI+DI so,

  • 21=17+DI [AD=21(given) and AI=17 (by the theorem)]

thus,

  • DI=21-17=\boxed{4}

By the theorem we obtain:

  • DI=DG=4

Similarly,DC=DG+CH therefore,

  • DC=4+2.5=\boxed{6.5}

Now <u>finding</u><u> </u><u>the</u><u> </u><u>Perimeter</u><u> </u><u>of </u><u>ABCD</u>

  • P_{\text{ABCD}}=\text{AB+AD+BC+DC}

substitute what we have and got

  • P_{\text{ABCD}}=\text{29+21+14.5+6.5}

simplify addition:

  • P_{\text{ABCD}}=\boxed{71}

hence,

the Perimeter of ABCD is <u>7</u><u>1</u>

4 0
3 years ago
How would you find the values of x and y?
Ipatiy [6.2K]
If you havent learnt Sin, Cos yet, let me know, so we can try the other solutions.

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4 years ago
Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1
garik1379 [7]

Answer:

d=1.28\times 10^{-6}\ g/cm^3

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3

So, the density of the bag is 1.28\times 10^{-6}\ g/cm^3.

7 0
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