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vodka [1.7K]
2 years ago
7

Cuales son los valores

Mathematics
1 answer:
Butoxors [25]2 years ago
4 0

Answer:

Can you please translate this into English so I can help you?

Step-by-step explanation:

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\dfrac{x^2-x-12}{2x}:\dfrac{x^2-2x-8}{4x^2}=\dfrac{x^2-x-12}{2x}\cdot\dfrac{4x^2}{x^2-2x-8}\\\\=\dfrac{(x+3)(x-4)}{2x}\cdot\dfrac{2x\cdot2x}{(x+2)(x-4)}=\dfrac{(x+3)}{1}\cdot\dfrac{2x}{(x+2)}\\\\=\boxed{\dfrac{2x^2+6x}{x+2}}

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