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lions [1.4K]
3 years ago
7

Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio

n for the league. Team Season Winning Percentage 1 0.750 2 0.750 3 0.200 4 0.600 5 0.200 (a) 0.79 (b) 0.251 (x) 0.56 (d) 0.063
Mathematics
1 answer:
Masja [62]3 years ago
7 0

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2}  } }{N} }

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\

3. Caclulate Standard deviation:

SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2}  } }{5} }

SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251

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The answer is 114.5%.

Let the original population be denoted by x.

Now, let's go through the percentage increase per year.

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Hence, the overall percentage increase in these 4 years is 114.5%.

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2 years ago
If an object is dropped from a height of 55 feet, the function d = -16^2 + 55 gives the height of the object after t seconds. Gr
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Answer:

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Step-by-step explanation:

Looks like the function is  d = -16t^2 + 55    ( you left out the t)

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