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3 years ago

Help plzzzzzzzzzzzzz

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

Y = -5/4x - 3

Step By Step Explanation
2 = -5/4(-4) + b
2 = 5 + b
-5 -5
-3 = b

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A bicycle lock has a four-digit code. The possible digits, 0 What is the probability that the lock code will begin with

nika2105 [10]

Answer:

0.1-0.6

Step-by-step explanation:

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities

the second digit is any of the remaining 9, after having picked one.

and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

P(first digit is five)=

b. What is the probability that the lock code will not contain the number 0?

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6

8 0

3 years ago

Read 2 more answers

Can anybody help me with these two questions

sladkih [1.3K]

Answer:

#1 is 39

#2 is 10 1/2

Step-by-step explanation:

Hopefully this helped, if not HMU and I will try my best to get you a better answer!

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3 years ago

What is the measure of 162 A. 324° B. 162° O C. 81° D. 72°

telo118 [61]

Answer:

Step-by-step explanation:

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3 years ago

Which values of P and Q result in an equation with no solutions?

Ad libitum [116K]

Try this solution/explanation:

way 1:

rule: for an equation where no roots P+Q=0. It means, Px-Qx=0, ⇔ x(P-Q)=0, ⇔ P=Q.

for answer 'D' P=Q=15.

way 2:

rule: if an equation of the line has a form y=kx+b, then y₁||y₂ if k₁=k₂. It means, for y₁=Px-45 || y₂=Qx+75, then P=Q. P=Q, if 'D' answer.

Answer: D

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3 years ago

An academic department with five faculty members narrowed its choice for department head to either candidate a or candidate

Fantom [35]

The probability that the first two votes drawn are both for candidate a is given by:
3C2/5C2 = 3/10
Having drawn two votes for candidate a on the first two draws, there are 2 votes for candidate b and one vote for candidate a remaining. The probability that a vote for candidate b will be drawn on the third draw is:
2/3.
After the first three draws, there reains one vote for candidate a and one vote for candidate b. The probability that a vote for candidate a will be drawn on the fourth draw is:
1/2.
The probability of the ordering aabab is therefore given by:
$\frac{3}{10}\times\frac{2}{3}\times\frac{1}{2}=\frac{6}{60}$
The answer is: 0.1.

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