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Kobotan [32]
3 years ago
12

What is the answer of 24:93=5:?

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

24 : 93=5 : 19.375

Step-by-step explanation:

24:93=5:?

24/93=5/x

x = 5 x 93/24 = 19.375

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How are the perimeters of the preimage polygon and the image polygon related? Explain.
Romashka-Z-Leto [24]

The difference between Pre-Image and Image is given as follows:

  • Image is the shape AFTER a transformation is the picture of the transformation.
  • A transformation's preimage is the shape BEFORE the change.

<h3>How do you define relationships between Image and Preimage?</h3>

Usually, the difference between image and pre-image is the way or method of transformation.

<h3>What is transformation in math?</h3>

A transformation is a broad phrase covering four distinct methods of changing the shape and/or location of a point, line, or geometric figure.

The Pre-Image is the original shape of the item, and the Image during the transformation is the final shape and location of the object.

The types of transformation in math are;

  • translation
  • rotation
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7 0
1 year ago
consider the line y=2/3x-0 find the equation of the line that is parallel to this line and passes through the point(8, 4).
Mila [183]
To find the equation take the slope 2/3 y-y(1)=m(x-x(1) y-4=2/3(x-8) = 2/3x-16/3 Next solve for y y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator) y=2/3x-16/3 + 12/3 y=2/3x-4/3
4 0
3 years ago
What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)
Pachacha [2.7K]

Answer:

The third option listed: \sqrt[3]{2x} -6\sqrt[3]{x}\\

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

7\sqrt[3]{2x}  -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x}  -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x}  -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}

Therefore this is the simplified radical expression: \sqrt[3]{2x} -6\sqrt[3]{x}\\

5 0
3 years ago
Solve for F: C=5/9(F-32)<br> please explain process thanks
timama [110]
C=\frac{5}{9}(F-32)\ \ \ \ /\cdot\frac{9}{5}\\\\F-32=\frac{9}{5}C\ \  \ \ /+32\\\\F=\frac{9}{5}C+32\\\\F=\frac{9C}{5}+\frac{160}{5}\\\\F=\frac{9C+160}{5}
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3 years ago
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