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andrey2020 [161]
2 years ago
14

Sometimes one action has an effect on another action. The cause is the reason something happens. The effect is the result. Sam w

anted to print a digital photo that is 5 inches wide and 7 inches long. Sam can make a table to understand cause and effect.
What if Sam accidentally printed a photo that is 6 inches wide and 8 inches long?

Cause Effect
The wrong size photo was printed. Each side of the photo is a length.


Use the information and the strategy to complete the answers to the problems.

What effect did the mistake have on the perimeter of the photo?

The perimeter by
inches.

What effect did the mistake have on the area of the photo?

The area by
square inches.
Mathematics
1 answer:
Gre4nikov [31]2 years ago
6 0

Answer: The mistake caused the perimeter to increase by 4 inches

The mistake caused the area to increase by 13 square inches

Step-by-step explanation: The original dimensions have been given as 5 inches by 7 inches. If this measurement had been correctly used, the perimeter was supposed to be;

Perimeter = 2(L + W)

Perimeter = 2(5 + 7)

Perimeter = 2(12)

Perimeter = 24 inches

Also the area was supposed to be;

Area = L x W

Area = 5 x 7

Area = 35 square inches

However, Sam accidentally printed a photo that is 6 inches by 8 inches, therefore the effect would be as follows;

Perimeter = 2(L + W)

Perimeter = 2(6 + 8)

Perimeter = 2(14)

Perimeter = 28 inches

And the Area would be

Area = L x W

Area = 6 x 8

Area = 48 square inches

From the calculations so far, the mistake would cause the perimeter to increase by 4 inches (28 inches - 24 inches).

Also the area would likewise increase by 13 inches (48 inches - 35 inches).

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Jose's car can drive 12 miles on each gallon of gas. How many gallons will he need to drive 3,298 miles?✱
masya89 [10]

Answer:

274.84 gallons.

Step-by-step explanation:

Divide 3,298 by 12

3298/12 =274.84

6 0
3 years ago
Find the number of diagonals of a regular polygon whose interior angle measures 144 degrees?
djverab [1.8K]
Diagonals are = n - 2

Interior = 144

Exterior angle = 180 - 144 = 36

Formula for exterior of  a regular polygon given the number of sides:

= 360/n

36 = 360/n

n = 360/36 = 10

n = 10

Number of diagonals = n - 2 = 10 - 2 = 8

8 diagonals.
7 0
3 years ago
Read 2 more answers
Y>= -5x + 8 what is m?​
Sonbull [250]

Answer:

The slope = -5

Step-by-step explanation:

y ≥ -5x + 8

Look at the problem as y = -5x + 8 and compare to the slope intercept form. The slope = -5

6 0
2 years ago
A car salesman makes 2% commission on all cars, x, that he sells. How much commission does he make?
HACTEHA [7]

Answer: 0.02x

Step-by-step explanation:

The value of the cars the salesman makes is x in this instance.

The salesman makes a 2% commission on every sale so this can be represented by multiplying 2% by the value of the cars which in this case is x.

= 2% * x

= 0.02 * x

= 0.02x

If for instance he sells $40,000 worth of cars, his commission would be:

= 0.02 * x

= 0.02 * 40,000

= $800

8 0
3 years ago
The length l, width w, and height h of a box change with time. At a certain instant the dimensions are l = 3 m and w = h = 6 m,
Gemiola [76]

Answer:

a) The rate of change associated with the volume of the box is 54 cubic meters per second, b) The rate of change associated with the surface area of the box is 18 square meters per second, c) The rate of change of the length of the diagonal is -1 meters per second.

Step-by-step explanation:

a) Given that box is a parallelepiped, the volume of the parallelepiped, measured in cubic meters, is represented by this formula:

V = w \cdot h \cdot l

Where:

w - Width, measured in meters.

h - Height, measured in meters.

l - Length, measured in meters.

The rate of change in the volume of the box, measured in cubic meters per second, is deducted by deriving the volume function in terms of time:

\dot V = h\cdot l \cdot \dot w + w\cdot l \cdot \dot h + w\cdot h \cdot \dot l

Where \dot w, \dot h and \dot l are the rates of change related to the width, height and length, measured in meters per second.

Given that w = 6\,m, h = 6\,m, l = 3\,m, \dot w =3\,\frac{m}{s}, \dot h = -6\,\frac{m}{s} and \dot l = 3\,\frac{m}{s}, the rate of change in the volume of the box is:

\dot V = (6\,m)\cdot (3\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot (3\,m)\cdot \left(-6\,\frac{m}{s} \right)+(6\,m)\cdot (6\,m)\cdot \left(3\,\frac{m}{s}\right)

\dot V = 54\,\frac{m^{3}}{s}

The rate of change associated with the volume of the box is 54 cubic meters per second.

b) The surface area of the parallelepiped, measured in square meters, is represented by this model:

A_{s} = 2\cdot (w\cdot l + l\cdot h + w\cdot h)

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time:

\dot A_{s} = 2\cdot (l+h)\cdot \dot w + 2\cdot (w+h)\cdot \dot l + 2\cdot (w+l)\cdot \dot h

Given that w = 6\,m, h = 6\,m, l = 3\,m, \dot w =3\,\frac{m}{s}, \dot h = -6\,\frac{m}{s} and \dot l = 3\,\frac{m}{s}, the rate of change in the surface area of the box is:

\dot A_{s} = 2\cdot (6\,m + 3\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m+6\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m + 3\,m)\cdot \left(-6\,\frac{m}{s} \right)

\dot A_{s} = 18\,\frac{m^{2}}{s}

The rate of change associated with the surface area of the box is 18 square meters per second.

c) The length of the diagonal, measured in meters, is represented by the following Pythagorean identity:

r^{2} = w^{2}+h^{2}+l^{2}

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time before simplification:

2\cdot r \cdot \dot r = 2\cdot w \cdot \dot w + 2\cdot h \cdot \dot h + 2\cdot l \cdot \dot l

r\cdot \dot r = w\cdot \dot w + h\cdot \dot h + l\cdot \dot l

\dot r = \frac{w\cdot \dot w + h \cdot \dot h + l \cdot \dot l}{\sqrt{w^{2}+h^{2}+l^{2}}}

Given that w = 6\,m, h = 6\,m, l = 3\,m, \dot w =3\,\frac{m}{s}, \dot h = -6\,\frac{m}{s} and \dot l = 3\,\frac{m}{s}, the rate of change in the length of the diagonal of the box is:

\dot r = \frac{(6\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot \left(-6\,\frac{m}{s} \right)+(3\,m)\cdot \left(3\,\frac{m}{s} \right)}{\sqrt{(6\,m)^{2}+(6\,m)^{2}+(3\,m)^{2}}}

\dot r = -1\,\frac{m}{s}

The rate of change of the length of the diagonal is -1 meters per second.

6 0
3 years ago
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