Answer:
Step-by-step explanation:
It is expected the spinner to land on Red 1/5 times.
<u>If the spinner is spun 40 times, then it should land on Red:</u>
<u>And it should not land on red:</u>
- (1 - 1/5)*40 = 4/5*40 = 32 times
Correct choice is D
Answer:
Each would equal 10 lbs.
Step-by-step explanation:
60 pounds all together is the weight of 6 boxes, so if you divide 60 by 6, you'll get 10 lbs for each box.
9514 1404 393
Answer:
2√30 ∠-120°
Step-by-step explanation:
The modulus is ...
√((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30
The argument is ...
arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle
The polar form of the number can be written as ...
(2√30)∠-120°
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<em>Additional comments</em>
Any of a number of other formats can be used, including ...
(2√30)cis(-120°)
(2√30; -120°)
(2√30; -2π/3)
2√30·e^(i4π/3)
Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).
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At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)
Step-by-step explanation:
We can immediately eliminate answers B and C because we have >, meaning that the circle on the number line has to be open.
-2x+7>17
subtract 7 on both sides
-2x>10
divide by -2. remember that dividing by a negative flips the greater than or less than sign.
x<-5
the answer is D
Answer:
- b/a
- 16a²b²
- n¹⁰/(16m⁶)
- y⁸/x¹⁰
- m⁷n³n/m
Step-by-step explanation:
These problems make use of three rules of exponents:
In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)
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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.
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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.
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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.
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4. This works the same way the previous problem does.
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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.
