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ankoles [38]
4 years ago
11

73,569 round to the nearest ten thousand

Mathematics
2 answers:
stellarik [79]4 years ago
5 0

The answer is 74,000.

 Remember, 5 or more - round up. 4 and below - round down. Hope this Help!

nevsk [136]4 years ago
3 0
70,000 because the 3 in the thousands place is less than 5.
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−1 ≤ x/-4 − 3<br><br>Solve the inequality. Show all steps.
makkiz [27]

Answer:

≤ − 8

Step-by-step explanation:

-1 ≤ \frac{x}{-4} -3

4 ×(-1) ≤ 4 × \frac{x}{-4} -4×3

-4 × (-1) ≤ -x - 4×3

-4 ≤ -x - 12

x ≤ -12 + 4

x ≤ -8

4 0
2 years ago
Set B is defined as B={x|x is an integer}. Name two elements of B.
jenyasd209 [6]
By definition we have an integer number given by:
 An integer is an element of the numeric set that contains the natural numbers {N} = {1,2,3,4, ...}, its opposite and zero.
 On the number line we find the negative numbers to the left of the zero and to its right the positive numbers.
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 Answer:
 
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option D
7 0
4 years ago
Read 2 more answers
What is an example of when you would want consistent data and, therefore, a small standard deviation?
steposvetlana [31]

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

\bar X=\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

8 0
3 years ago
The diameter of bushings turned out by a manufacturing process is a normally distributed random variable with a mean of 4.035 mm
Andrew [12]

A) the z score for 95% is 1.96

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1.96 x 0.005 = 0.0098

Now add and then subtract that from the mean:

4.035 - 0.0098 = 4.0252

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The interval is (4.0252, 4.0448)

B) 4.035 +/- 1.96 x sqrt( 0.005/sqrt(25))

= 4.035 +/-0.00196

Answer: ( 4.033, 4.037)

C) the conclusion is that both 4.020 and 4.055 are out of the range.

4.020 is below the lowest range and 5.055 is higher than highest range.

6 0
4 years ago
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viva [34]

Answer:

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Step-by-step explanation:

We already know that the answer is between c and d because the correlation coefficient negative.

We just have to figure out whether it is strong or weak.

In general, anything between -.7 and -1 is considered to have a strong correlation. -.8 is in between -.7 and -1 therefore the correlation is best described as strong negative.

4 0
3 years ago
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