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kodGreya [7K]
3 years ago
7

Set B is defined as B={x|x is an integer}. Name two elements of B.

Mathematics
2 answers:
jenyasd209 [6]3 years ago
7 0
By definition we have an integer number given by:
 An integer is an element of the numeric set that contains the natural numbers {N} = {1,2,3,4, ...}, its opposite and zero.
 On the number line we find the negative numbers to the left of the zero and to its right the positive numbers.
 We have then, according to the definition, that the following are whole numbers:
 -527, 1
 Answer:
 
B = {x | x is an integer}
 
-527 ∈ B
 
1 ∈ B
 
option D
Maru [420]3 years ago
4 0

Answer:D is the answer

Step-by-step explanation:

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the area of a triangle is 384 square feet. If its base is 8 feet longer than its altitude, find the length of the base and the a
REY [17]
A=1/2bh
b=8+h
A=384

384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
minus 768 both sides
0=b^2+8b-768
factor
0=(b-24)(b+32)
set to zero
b-24=0
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false, legnths cannot be negative

b=24
24=8+h
minus 8
16=h

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6 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

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Answer:

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Step-by-step explanation:

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