A=1/2bh
b=8+h
A=384
384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
minus 768 both sides
0=b^2+8b-768
factor
0=(b-24)(b+32)
set to zero
b-24=0
b=24
b+32=0
minus 32
b=-32
false, legnths cannot be negative
b=24
24=8+h
minus 8
16=h
base=24ft
altetude=16ft
Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.
Let AD=x, Since given AB=3
AD+DB=3
x+DB = 3
DB = 3-x
Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem



Since given AD=BC,let us plugin BC=x in above step.


6x=11
x=
Now we know AD=x=
and given CD=√2.
Let us apply Pythagoras theorem for ΔACD



= 2.315cm
Answer:
Hi how are you
Step-by-step explanation:
Have a nice day
171/500....... is the answer