All categories

3 years ago

Why does the Separatists wanted to establish their own colony in New England?

Mathematics

2 answers:

Free_Kalibri [48]3 years ago

8 0

Answer:

Separatists wanted to establish thir own colony in New England because they were scared of the protects caused by the Loyalits. Aslo, it was the patriots who wanted their own conlony in America. Not the Separatists.

Step-by-step explanation:

Sindrei [870]3 years ago

3 0

Answer:

it was the Puritans the ones who established it.

Step-by-step explanation:

You might be interested in

The difference of the squares of two positive consecutive even integers is 84. Find the integers. Use the fact that, if x repre

Art [367]

Has gawd though of the letter a

7 0

2 years ago

Pls help me solve this please I will give 70 points please help

Mashutka [201]

Answer:

Fraction Form: $\frac{2187}{4000000}$

Decimal Form: $0.000547$

Step-by-step explanation:

$=\frac{5}{256} * \frac{3}{5}^1^2 / \frac{3}{5}^5$

$\frac{3}{5}^1^2/\frac{3}{5}^5=\frac{2187}{78125}$

$=\frac{5}{256}*\frac{2187}{78125}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}$

$\frac{5*2187}{256*78125}$

$\mathrm{Factor\:the\:number:\:}\:78125=5\cdot \:15625$

$=\frac{5*2187}{256*5*15625}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=\frac{2187}{256*15625}$

$\mathrm{Multiply\:the\:numbers:}\:256\cdot \:15625=4000000$

$\frac{2187}{4000000}$

[RevyBreeze]

5 0

2 years ago

Can someone help me with this question please

Olegator [25]

To land on 0 the number would need to end with a .5 or .0 since that is the only way .0 can occur with counting down by.5( half)

8 0

2 years ago

If f(x) = 8x2 + 4x - 12. Find f(2) f(2)=

posledela

Answer:

f(2) = 28

Step-by-step explanation:

$\rm f(x) = 8 {x}^{2} + 4x - 12$

$\rm Evaluate \: 8 x^2 + 4 x - 12 \: where \: x = 2: \\ \\ \rm \implies f(2) = 8 \times {2}^{2} + 4 \times 2 - 12 \\ \\ \rm \implies f(2) = 8 \times 4 + 8 - 12 \\ \\ \rm \implies f(2) = 32 - 4 \\ \\ \rm \implies f(2) = 28$

3 0

2 years ago

Outline the process for inscribing a regular hexagon in a circle. Perform the construction in GeoGebra

mr_godi [17]

The following are the general steps to draw a hexagon inscribed in a circle:

First draw a circle with center A through B:

Then the intersection points will be vertex C and vertex D of the hexagon. Doing this for each vertex (from left to right) we will get the following:

4 0

1 year ago