Answer:
No. The new height of the water is less than the height of the glass(6.33 cm<10 cm)
Step-by-step explanation:
-For the water in the glass to overflow, the volume of the inserted solid must be greater than the volume of the empty space or the ensuing height of water >height of glass.
#Volume of the golf ball:
#The volume of the water in the glass:
We then equate the two volumes to the glass' volume to determine the new height of the water:
Hence, the glass will not overflow since the new height of the water is less than the height of the glass(6.33 cm<10cm).
1 and 2 are equations and 3 is a solution
GCF = 20
Reduce the fraction by dividing
the numerator and denominator by 20
and get the simplified answer
<span><span>20 ÷ 20=1 || 80 ÷ 20</span>=4
<em>1/4</em> is your answer! :D</span>
Answer:
P( That it will take over 10 years or more of a year with a rainfall above 50inches) = (0.9938)^10
Step-by-step explanation:
Since the annual rainfall is normally distributed,
Given: that
Mean (µ )= 40
and σ = 4.
Let X be normal random variables of the annual rainfall.
P(that there will be over 10 years or more before a year with a rainfall above 50 inches)
P(>50) = 1-P[X ≤50]
1 - P[X- μ/σ ≤ 50 - 40/4]
=1 - P [Z≤ 5/2]
=1 -Φ(5/2)
=1 - 0.9939
= 0.0062
P( the non occurrence of rainfall above 50 inches)
= 1-0.0062
=0.9938
ASSUMPTION:
P( That it will take over 10 years or more of a year with a rainfall above 50inches) =
Answer:
7, -7
Step-by-step explanation:
7(-7) = 49
7 - 7 = 0
