Answer:
B and C work. A and D do not.
Step-by-step explanation:
This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.
A]
5n + 6
Let n = 1
5(1) + 6
5 + 6= 11
However there is trouble beginning with n = 2
5*2 + 6
10 + 6
16 All you need is one wrong answer and the choice is toast. So A won't work.
================
Try D
6(n - 1)+ 5
n=0
6*(-1) + 5
-6 + 5
- 1
And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse. D is not one of the answers.
=============
B
Let n = 1
6(1) + 5
6 + 5
11 The first term works.
n = 2
6*(2) + 5
12 + 5
17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.
n = 3
6*(3) + 5
18 + 5
23 And this also works. I'll let you deal with n = 4
========
C
n = 0
6(0 + 1) + 5
6*1 + 5
6 + 5
11
n = 1
6(1 + 1) + 5
6*2 + 5
12 + 5
17 which works.
So C is an answer.
Let , coordinate of points are P( h,k ).
Also , k = 3h + 1
Distance of P from origin :
![d=\sqrt{h^2+k^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bh%5E2%2Bk%5E2%7D)
Distance of P from ( -3, 4 ) :
![d=\sqrt{(h+3)^2+(k-4)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28h%2B3%29%5E2%2B%28k-4%29%5E2%7D)
Now , these distance are equal :
![h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2](https://tex.z-dn.net/?f=h%5E2%2B%283h%2B1%29%5E2%3D%28h%2B3%29%5E2%2B%283h%2B1-4%29%5E2%5C%5C%5C%5Ch%5E2%2B%283h%2B1%29%5E2%3D%28h%2B3%29%5E2%2B%283h-3%29%5E2)
Solving above equation , we get :
![P=(\dfrac{16}{21},\dfrac{23}{7})](https://tex.z-dn.net/?f=P%3D%28%5Cdfrac%7B16%7D%7B21%7D%2C%5Cdfrac%7B23%7D%7B7%7D%29)
Hence , this is the required solution.
Answer:
B. 4
Step-by-step explanation:
The degree of the polynomial (the exponent of the highest term) is the total number of roots (including imaginary roots).
The degree of this polynomial is 4, so there are 4 roots.
Answer:
15 routes
Step-by-step explanation:
3 x 5 = 15 routes
Use the tangent-chord theorem:
The included chord-tangent angle is half the size of the intercepted arc.
The intercepted arc is "c".
The included chord-tangent-angle is the supplement of 110=70 degrees.
Therefore from the tangent-chord theorem, 70 degrees = half the size of arc "c"
=>
arc "c" = 2*intercepted angle = 2*70 degrees = 140 degrees.