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pentagon [3]
3 years ago
15

Help ASAP!!!! Ill make you brianlest plssss 2- pst

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

1. linear = y= mx+b so it would be y=3x+5

not prime would be y= x^2 since there is not limr number in the equation

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Help me , I will mark first answer brainliest
lana [24]

Answer:

x=6;    ∠b=68°

Step-by-step explanation:

8x+74+2x+56=190

10x+130=190

10x=60

x=6

2x+56

12+56

68

8 0
3 years ago
Read 2 more answers
O'Connor breakfast foods produced 6,552 of crispy corn cereal. the company wants to put the cereal into boxs that hold 12 ounces
Olegator [25]

That would be 6552 / 12 =   546 boxes.

(Im assuming that its 6552 ounces of cereal )

5 0
3 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 44 o
Cerrena [4.2K]

Answer:

a) No 95% of values will fall between (24;64); 68,27% will fall between (34;54)

b)71,83 % will fall between 34 and 64 ounces

Step-by-step explanation:

Empirical rule establishes, for a  normal distribution with mean μ and σ as standard deviation:

In interval   μ  ±  σ    or   ( μ  +  σ ;  μ  -  σ) we should find 68.27 % of all values of the population, and by simmetry 68.27/2 = 34,14 % should be over the mean and the other half would  be values below the mean

Therefore in our case

μ  +  σ  =  44 + 10  =  54

And

μ  -  σ  = 44 - 10   = 34

a) Then  68,34 % of values will fall in this interval

We know now that value 34 is 1* σ   below the mean, and is at the limit of 34,14 %

b) μ  +  2*σ  =   44 * 2*10  =  44 + 20  =  64

64 is the upper limit for the interval   μ  +  2*σ  and we know that 95.45 % of all values will fall between (  μ  -  2*σ  ;  μ  +  2*σ ) and by simmetry just one side of this interval (the right side ) will have 95.45/2 = 47;73 %

Then in interval going from ( 34 ; 64 ) we shoud find 47.73 + 34,14

71,83 % of all values will fall between 34 and 64

7 0
3 years ago
For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.
Flauer [41]

 

\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\

.

\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276

.

\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}    

 

 

8 0
3 years ago
I can't figure out how to do this problem. Could somebody help me?
Verizon [17]

start by plugging in the value you already have, in this case, 5 for y.

-4x-3(5)=17

-4x-15=17

-4x=32

x=-8

however, since a is a+1, a would be 7 (making x 8)

also plz tell me if i read this wrong and it’s actually 1,5 rather than a+1 and 5 cause if i did i’m so sorry lol.

8 0
3 years ago
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