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adoni [48]
2 years ago
14

Given the graph of f(x), fund the value of f(4). Options: -1, 1, 2, 4

Mathematics
2 answers:
ArbitrLikvidat [17]2 years ago
5 0

Answer:

2

Step-by-step explanation:

the y-value of an x-value of 4, according to the graph, is 2

Ede4ka [16]2 years ago
5 0

Answer:

2

Step-by-step explanation:

This question is asking you to find the value of f(x) which is really just the y-coordinate. You need to find the y-coordinate for f(4), which means when x=4. So, go to the line on the graph where x=4 and find the point that lies there. In this case, when x=4 the y-coordinate is 2. The coordinates for this point are (4,2) and can be seen on the far right side of the graph.

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Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following: {1,2,2,3,3,4} on one die and {1,3,
ozzi

Step-by-step explanation:

Sample space, S = {(1,1),(1,3),(1,4),(1,5),(1,6),(1,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(4,1),(4,3),(4,4),(4,5),(4,6),(4,8)}

These dice will give a sum of 2 with N={(1,1)}, which only has 1 combination

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\frac{1}{36}

8 0
3 years ago
CAN SOMEONE HELP ME PLEASE ASAP!?
Naddika [18.5K]

Answer:

First option is the correct answer.

14.29\: m^2

Step-by-step explanation:

Area of circular pond

= \pi {r}^{2}  \\  \\  = 3.14 {(7)}^{2}  \\  \\   = 153.86 \:  {ft}^{2}\\\\=\frac{153.86}{(3.2808)^2}\:m^2\\\\=14.29\: m^2

5 0
3 years ago
Read 2 more answers
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Gekata [30.6K]

Answer:

The answer for this question is c

8 0
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Answer:

Dear Students and Families: It has come to our attention that families and students have been contacted regarding the replacement of chrome books being used by students. Please disregard these requests, as they are not affiliated with GEE Prep. If anyone reaches out to you, please contact us and we will look into it. Only GEE Prep staff will reach out regarding the replacement of any student chrome books. Thank you.

Step-by-step explanation:

6 0
3 years ago
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Mariulka [41]
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