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jasenka [17]
3 years ago
9

A newborn baby what weighs 3⁷ kilograms. An adult blue whale weighs 81 times the newborn. How many kilograms does the adult blue

whale weigh? Write your answer as a power of 3.​
Mathematics
1 answer:
kherson [118]3 years ago
7 0

Answer:

2187

Step-by-step explanation: 27 times 81 equals 2187

You might be interested in
Use the law of cosines to find the value of 2*4*5 cos theta
sweet-ann [11.9K]
We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90

3 0
3 years ago
Read 2 more answers
2. Four less than six times a number is 32. Write and solve an equation.
zhenek [66]

Answer:

6x - 4 = 32. The variable (times a number) is equal to 6.

Step-by-step explanation:

So this equation is basically asking you to formulate an equation using only the words given. For this equation, let's use a variable in place of the part where it says "times a number." When a question says that phrase, that means that they are telling you to use a variable in place of a mystery number. A variable is a letter in place of a mystery number. Knowing this, let's now solve the equation. We will use the variable x in place of our mystery number.

Four less than 6 times a number: 6x - 4 _ __.

Now we can add the equal sign and the 32: 6x - 4 = 32.

We can now solve. Add 4 to both sides of the equation to cancel out the -4:

6x - 4 = 32

    <u>+4   + 4</u>

6x  =    36

Now we divide 6 into both sides of the equation to single out the x.

<u>6x = 36</u>

6      6

36/6 = 6, so:

x = 6

I hope that this helps.

8 0
2 years ago
The height of the tunnel at the center is 35ft, and the vertical clearance must be 21 ft at a point of 8ft from the center. Find
Zinaida [17]

Answer:

y=-0.215x^2+35

Step by Step:

Let, h=0,  k=35, x=8, y=21

We know that, the general equation of the parabola.

   y-k = a(x-h)^2

\Rightarrow y=a(x-h)^2+k  .........(i)

Substitute the  value of h, k, x, y in equation (i) and find the value of a.

  21=a(8-0)^2+35

\Rightarrow 21=a\times 8^2+35

\Rightarrow 21=64a+35

\Rightarrow 64a=21-35

\Rightarrow 64a=-14

\Rightarrow a=\frac{-14}{65}

\Rightarrow a=-0.215

Hence, the equation of the parabola is:

y=-0.215x^2+35

8 0
3 years ago
Help please quickly!!!!!!1
IgorLugansk [536]

Answer:

9

Step-by-step explanation:

As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.

Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; (a^2 + b^2 = c^2), where (a) and (b) are the legs of the right triangle, or the sides adjacent to the right angle. (c) is the hypotenuse or the side opposite the right angle.

Substitute in the given values and solve, note that (a) represents the unknown leg (side).

a^2 + b^2 = c^2\\\\a^2 + (\sqrt{19})^2 = (100)^2\\\\a^2 + 19 = 100

Inverse operations,

a^2 + 19 = 100\\-19\\\\a^2 = 81\\\\a = \sqrt{81}\\\\a = 9

8 0
3 years ago
With reference to the figure, sin X equals?<br> 1.) 0.250<br> 2.)0.447<br> 3.)0.894<br> 4.)1
Flura [38]

Answer:

3.) 0.894

Step-by-step explanation:

✔️First, find BD using Pythagorean Theorem:

BD² = BC² - DC²

BC = 17.89

DC = 16

Plug in the values

BD² = 17.89² - 16²

BD² = 64.0521

BD = √64.0521

BD = 8.0 (nearest tenth)

✔️Next, find AD using the right triangle altitude theorem:

BD = √(AD*DC)

Plug in the values into the equation

8 = √(AD*16)

Square both sides

8² = AD*16

64 = AD*16

Divide both sides by 16

4 = AD

AD = 4

✔️Find AB using Pythagorean Theorem:

AB = √(BD² + AD²)

AB = √(8² + 4²)

AB = √(64 + 16)

AB = √(80)

AB = 8.9 (nearest tenth)

✔️Find sin x using trigonometric ratio formula:

Reference angle = x

Opposite side = BD = 8

Hypotenuse = AB = 8.944

Thus:

sin(x) = \frac{opp}{hyp} = \frac{8}{8.944} = 0.894 (nearest thousandth)

6 0
3 years ago
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