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3 years ago

9

A newborn baby what weighs 3⁷ kilograms. An adult blue whale weighs 81 times the newborn. How many kilograms does the adult blue

whale weigh? Write your answer as a power of 3.

1 answer:

kherson [118]3 years ago

7 0

Answer:

2187

Step-by-step explanation: 27 times 81 equals 2187

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1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

<em /> $L \to$ <em> Letters</em>

<em /> $C \to$ <em> Cost</em>

<em />

Using proportional reasoning, we have:

$C = kL$

Where

<em /> $k \to$ <em> ratio of proportion</em>

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

<u>When C = 6.75, we have:</u>

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

<u>When L = 7, we have:</u>

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

<u>When L = 1, we have:</u>

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

<u>When L = 500, we have:</u>

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

<u>When C = 18.90, we have:</u>

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Read more about proportions at:

brainly.com/question/21126582

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2 years ago

Your little cousin will have a big animal-themed birthday party and you will help with the goody bags. Each bag will have a penc

Bas_tet [7]

Using the least common factor, it is found that:

a) 60 packages should be bought.

b) There will be 5 filled goody bags.

<h3>Least Common Factor:</h3>

The sizes of the packages are: 10, 6, 15 and 12.

To fill each bag and have no left-overs, the number of packages is the <u>least common factor</u> of these amounts.

The least common factor is found factoring the numbers into prime factors.

Item a:

10 - 6 - 15 - 12|2

5 - 3 - 15 - 6|2

5 - 3 - 15 - 3|3

5 - 1 - 5 - 1|5

1 - 1 - 1 - 1

Hence, lcf(10,6,15,2) = 2 x 2 x 3 x 5 = 60.

60 packages should be bought.

Item b:

Goody bags are in packages of 12, hence:

60/12 = 5.

There will be 5 filled goody bags.

To learn more about the least common factor, you can take a look at brainly.com/question/24873870

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2 years ago

Simplify the expression

kow [346]

Answer:

<h3> f(x) = 5x² + 2x</h3><h3> g(x) = 6x - 6</h3>

Step-by-step explanation:

$\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6$

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3 years ago

On the coordinate grid of a map, Josie's house is located at (2,7). Her school is located at (-5,5). If each map unit equals one

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I hope this helps you

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Sean earned an interest of $10,736 with simple annual interest account for 20 years at a rate of 6.1%. How much money did he ori

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Answer:

$750

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