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2 years ago

How do angles inside a polygon affect the sides of the polygon?

Mathematics

1 answer:

Scilla [17]2 years ago

8 0

Hello,

Let 's n the number of sides,

R the radius of the circonscrit circle,

c the side of the polygon (c like côté)

Angle in the center is 360/n and its half is 180/n

(c/2)/R=sin(180/n)

Inside angles are (180-360/n)/2 = 90-180/n (°)

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Arisa [49]

Step-by-step explanation:

26 * 14.6= 379.6 miles

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3 years ago

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2 years ago

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Could someone help me for this?

lina2011 [118]

Answer:

x = - $\frac{5}{3}$ , x = $\frac{5}{2}$

Step-by-step explanation:

to find the points of intersection equate the 2 equations , that is

7x - 15 = 10 + 12x - 6x² ( subtract 10 + 12x - 6x² from both sides )

6x² - 5x - 25 = 0 ← factor the quadratic on left side

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 6 × - 25 = - 150 and sum = - 5

the factors are - 15 and + 10

use these factors to split the x- term

6x² - 15x + 10x - 25 = 0 ( factor the first/second and third/fourth terms )

3x(2x - 5) + 5(2x - 5) = 0 ← factor out (2x - 5) from each term

(2x - 5)(3x + 5) = 0

equate each factor to zero and solve for x

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3 0

1 year ago

19. A quadratic equation is shown below.

victus00 [196]

Answer:

$\{\sqrt b, -\sqrt b\}$

Step-by-step explanation:

Given

$a^2 - b = 0$

Required

Determine the solution

Since b is a perfect square, the equation can be expressed as:

$a^2 - (\sqrt b)^2 = 0$

Apply difference of two squares:

$(a - \sqrt b)(a + \sqrt b) = 0$

Split:

$(a - \sqrt b)= 0 \ or\ (a + \sqrt b) = 0$

Remove brackets:

$a - \sqrt b= 0 \ or\ a + \sqrt b = 0$

Make a the subject in both equations

$a =\sqrt b \ or\ a =-\sqrt b$

The solution can be represented as:

$\{\sqrt b, -\sqrt b\}$

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2 years ago

Determine whether (18 + 35) × 4 = 18 + 35 ×4 is true or false. explain

fomenos

The first one is 212
and the second one is 158
so yes it is false they do not equal

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2 years ago