All categories

3 years ago

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 4 cos 5θ

Mathematics

1 answer:

S_A_V [24]3 years ago

7 0

Answer:

f(x) is an even if and only if f(-x) = f(x). f(x) is an odd if and only if f(-x) = -f(x). We have r(-θ) = r(θ). Therefore the graph of r(θ) is symmetric about the y-axis.

I hope it ehslp

have a great day

# Liliflim

You might be interested in

Answer question one and show work.

likoan [24]

Answer:

x = 28

Step-by-step explanation:

angle 1 and angle 2 are complementary (their sum is 90°)

x + 5 + 2x + 1 = 90 add like terms

3x + 6 = 90 subtract 6 from both sides

3x = 84 divide both sides by 3

x = 28

3 0

3 years ago

How many isosceles triangles are in a rectangle

kiruha [24]

There are 4 isosceles triangles in a rectangle:)

8 0

3 years ago

Read 2 more answers

In 2010 the Internal Revenue Service allowed a $5,150 deduction for each dependent. In 2005 it was a $3,200. If a family has fiv

Aleks04 [339]

5x5,150 =$25,750 = Answer

Deductions per dependent $5,150 times 5 in 2010

6 0

3 years ago

Help with num 9 please. thanks

Alik [6]

Answer:

See Below.

Step-by-step explanation:

We want to show that the function:

$f(x) = e^x - e^{-x}$

Increases for all values of x.

A function is increasing whenever its derivative is positive.

So, find the derivative of our function:

$\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]$

Differentiate:

$\displaystyle f'(x) = e^x - (-e^{-x})$

Simplify:

$f'(x) = e^x+e^{-x}$

Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of x.

8 0

4 years ago

Please help asap. due today

Ksivusya [100]

Answer:

ASA

Step-by-step explanation:

∠BAC ≈ ∠CAD

AC = AC

∠BCA ≈ ∠ACD

5 0

3 years ago