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storchak [24]
3 years ago
7

You have taken over an abandoned project of drilling a water well. You find the hole is 22 feet deep. After 3 hours of drilling,

the depth is 33.4 ft. What depth would you expect to reach after 15 hours?
Mathematics
1 answer:
kondaur [170]3 years ago
6 0
33.4-22= 11.4
11.4/3= 3.8
3.8 is one hour. 
3.8*15
57 ft. for the 15 hours.
57+33.4= 90.4 ft.
The answer is 90.4 ft.
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Consider a circle. The length of the arc for the central angle of 45 degrees is 16cm, then the total circumference (perimeter) o
Amanda [17]

Answer:

b

Step-by-step explanation:

the arc length is calculated as

arc = circumference (C) × fraction of circle , then

16 = C × \frac{45}{360} = C × \frac{1}{8} ( multiply both sides by 8 )

128 = C

circumference of circle is 128 cm

5 0
2 years ago
What is the correct answer ? Please explain why !!!
tangare [24]
The answer would be to because you were add 2+3 which equals six and then you multiply 6 times 3 which equals 12
6 0
4 years ago
Read 2 more answers
For each, list three elements and then show it is a vector space.
Butoxors [25]

Answer:

(a) Three polynomials of degree 1 with real coefficients belong to the set P_1=\{a_0+a_1x\ | a_0, a_1 \in \mathbb{R} \}, then:

2+3x \in P_1

4.5+\sqrt2 x \in P_1

\log5+78x \in P_1

(b) Three polynomials of degree 1 with real coefficients that hold the relation a_0 - 2a_1 = 0 belong to the set P_2=\{a_0+a_1x\ | a_0-2 a_1 =0 \}. The relation between the coefficients is equivalent to a_1 = \frac{a_0}{2}, then:

4+2x \in P_2

13+6.5x \in P_2

10.5+5.25x \in P_2

Step-by-step explanation:

(a) Three polynomials of degree 1 with real coefficients belong to the set P_1=\{a_0+a_1x\ | a_0, a_1 \in \mathbb{R} \}, then:

  • 2+3x \in P_1
  • 4.5+\sqrt2 x \in P_1
  • \log5+78x \in P_1

A vector space is any set whose elements hold the following axioms for any \vec{u}, \vec{v} and \vec{w} and for any scalar a and b:

  1. (\vec{u} + \vec{v} )+\vec{w} = \vec{u} +( \vec{v} +\vec{w})
  2. There is the <em>zero element </em>such that: \vec{0} + \vec{u} = \vec{u} + \vec{0}
  3. For all element \vec{u}of the set, there is an element -\vec{u} such that: -\vec{u} + \vec{u} = \vec{u} + (-\vec{u}) = \vec{0}
  4. \vec{u} + \vec{v} = \vec{v} + \vec{u}
  5. a(b\vec{v}) = (ab)\vec{v}
  6. 1\vec{u} = \vec{u}
  7. a(\vec{u} + \vec{v} ) = a\vec{u} + a\vec{v}
  8. (a+b)\vec{v} = a\vec{v}+b\vec{v}

Let's proof each of them for the first set. For the proof, I will define the polynomials a_0+a_1x, b_0+b_1x and c_0+c_1x and the scalar h and g.

  1. (a_0+a_1x + b_0+b_1x)+c_0+c_1x = a_0+a_1x +( b_0+b_1x+c_0+c_1x)\\(a_0+b_0+c_0) + (a_1+b_1+c_1)x = (a_0+b_0+c_0) + (a_1+b_1+c_1)x and defining a_0+b_0+c_0 = \alpha_0 and a_1+b_1+c_1 = \alpha_1, we obtain \boxed{\alpha_0+\alpha_1x= \alpha_0+\alpha_1x} which is another polynomial that belongs to P_1
  2. A null polynomial is define as the one with all it coefficient being 0, therefore: \boxed{0 + a_0+a_1x = a_0+a_1x + 0 = a_0+a_1x}
  3. Defining the inverse element in the addition as -a_0-a_1x, then -a_0-a_1x + a_0 + a_1x = a_0+a_1x + (-a_0-a_1x)\\\boxed{(-a_0+a_0)+(-a_1+a_1)x = (a_0-a_0)+(a_1-a_1)x = 0}
  4. (a_0+a_1x) +( b_0+b_1x) =( b_0+b_1x) +( a_0+a_1x)\\(a_0+b_0)+(a_1+b_1)x = (b_0+a_0)+(b_1+a_1)x\\\boxed{(a_0+b_0)+(a_1+b_1)x = (a_0+b_0)+(a_1+b_1)x}
  5. a[b(a_0+a_1x)] = ab (a_0+a_1x)\\a[ba_0+ba_1x] = aba_0+aba_1x\\\boxed{aba_0+aba_1x = aba_0+aba_1x}
  6. \boxed{1 \cdot (a_0+a_1x) = a_0+a_1x}
  7. \boxed{a[(a_0+a_1x)+(b_0+b_1x)] = a(a_0+a_1x) + a(b_0+b_1x)}
  8. (a+b)(a_0+a_1x)=aa_0+aa_1x+ba_0+ab_1x\\\boxed{(a+b)(a_0+a_1x)= a(a_0+a_1x) + b (a_0+a_1x)}

With this, we proof the set P_1 is a vector space with the usual polynomial addition and scalar multiplication operations.

(b) Three polynomials of degree 1 with real coefficients that hold the relation a_0 - 2a_1 = 0 belong to the set P_2=\{a_0+a_1x\ | a_0-2 a_1 =0 \}. The relation between the coefficients is equivalent to a_1 = \frac{a_0}{2}, then:

  • 4+2x \in P_2
  • 13+6.5x \in P_2
  • 10.5+5.25x \in P_2

Let's proof each of axioms for this set. For the proof, I will define again the polynomials a_0+a_1x, b_0+b_1x and c_0+c_1x and the scalar h and g. Again the relation a_1 = \frac{a_0}{2} between the coefficients holds

  1. [(a_0+a_1x) +( b_0+b_1x)]+(c_0+c_1x) = (a_0+a_1x) +[( b_0+b_1x)+(c_0+c_1x)]\\(a_0+b_0+c_0) + (a_1+b_1+c_1)x = (a_0+b_0+c_0) + (a_1+b_1+c_1)x and considering the coefficient relation and defining a_0+b_0+c_0 = \alpha_0 and a_1+b_1+c_1 = \alpha_1, we have (a_0+b_0+c_0) + (a_1+b_1+c_1)x = (a_0+b_0+c_0) + (a_1+b_1+c_1)x\\(a_0+b_0+c_0) + \frac{1}{2} (a_0+b_0+c_0)x = (a_0+b_0+c_0) + \frac{1}{2} (a_0+b_0+c_0)x\\\boxed{\alpha_0 + \alpha1x = \alpha_0 + \alpha1x} which is another element of the set since it is a degree one polynomial whose coefficient follow the given relation.

The proof of the other axioms can be done using the same logic as in (a) and checking that the relation between the coefficients is always the same.

6 0
4 years ago
A scale drawing for a home construction project uses a scale factor of 3. The area of the actual rectangular family room is 198
11111nata11111 [884]

Answer:

22 sq feet

Step-by-step explanationt

8 0
3 years ago
Read 2 more answers
I really need help...
ira [324]
The 1st is 3 2/16

Good luck with the others.
3 0
3 years ago
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