A point T on a segment with endpoints D (1, 4) and F (7, 1) partitions the segment in a 3:1 ratio. Find T.
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1) P= 64 cm, width = x, length = 14 + x
64 = x + x + 14 + x + 14 + x
64 = 4x + 28
4x = 64 - 28
4x = 36
x = 36/ 4
x = 9
AREA = 9 x (9+14)
Area = 9 x 23
Area = 207 cm
2) smaller no. = y, bigger no. = x
x - y = 3
2x+1/2y=36
Next, multiply 2 to first equation and find y:
2x-2y=6
5/2y=30
y = 12
Substitue y to x-y=3 to find x,
x = 15
3) x = pencil, y = pen
5x + 4y = $6.15
8x + 3y = 9.85$
8x + 7y = ?
5x + 4y = 6.15$ multiply both sides by -3
8x + 3y = 9.85$ multiply both sides by 4
-15x + 32x = (-3)*6.15 + 4*9.85
7x = 19.87 multiply both sides by 8/7
8x = (8/7) x 19.87
Add both equations:
32y - 15y = 8x6.15 - 5*9.58
17y = 1.3
y = 91/17) x 1.3
7y = (7/17)x 1.3
8x + 7y = (8/7) x 19.87 + (7/17) x 1.3
8x + 7y = $23.244
4) 2l + 2w = 0
2 x 2l + 2 x 1/2w = 40 + 16
l+w = 20
4l+w = 56
I’ve got l = 12 and w = 8
5) answer: 28.56 feet (approx)
step-by-step explanation:
since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.
we have to find out the measurement of segment ab.
therefore, tan 55° = \frac{ab}{bc}
but bc = 20 feet.
⇒ tan 55 ° = \frac{ab}{20}
⇒ ab = 20 × tan 55 °
⇒ ab = 20 × 1.42814800674
⇒ ab = 28.5629601348 ≈ 28.56 feet
6) The answer is teh attachment !
7) 3x-x+2=4
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So hmmm check the picture below
so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both
in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3
now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"
because the parabola opens downwards, "p" is negative, and thus, -2
now, let's plug all those fellows in then
so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both
in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3
now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"
because the parabola opens downwards, "p" is negative, and thus, -2
now, let's plug all those fellows in then