Answer: D. 2(V[x} + V{x - 2}) Step-by-step explanation: As hinted in the question, we have to simplify the denominator. To understand it easier, let's imagine we have x - y in the denominator. If we multiply it with x + y we'll get x? - y, right? Check the next line: (x - y) (x + y) = x² + xy -xy - y? = x² - y? If we have the square of those nasty square roots, it will be much simpler to deal with. So, let's multiply the initial fraction using x+y, but with the real values: 4 x-2 x+Vx-2 x-2 4(Va+v-2) (V#)² -(væ–2)² Then we simplify: 4(va+væ-2) 4(Va+va-2) (Væ)2-(Va-2)2 2(Va + Va – 2) 4(va+va-2) (x) -(x-2) 2 Answer is D. 2(V{X} + v{x - 2})
