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3 years ago

Write the equation of a line passing through (4, -2) and parallel to y = 5/4 x - 2

Mathematics

1 answer:

ASHA 777 [7]3 years ago

7 0

Answer:

y = 5/4x -7

Step-by-step explanation:

y = mx + b

parallel line has same slope: 5/4

y = 5/4x + b

(4 , -2) -2 = 5/4 x 4 + b

b = -7

Formula: y = 5/4x -7

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2 years ago

In the sum of two numbers is 15 and the product is 56, what are the two numbers?

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3 years ago

When 3 times a number is subtracted from 10, the result is the sum of the number and 22

Arada [10]

Answer:

x = -6

Step-by-step explanation:

Let the number be x

Condition:

=> 10-3x = x+22

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3 years ago

Read 2 more answers

What is the measure of the missing angle?

goblinko [34]

Answer:

The missing angle measures also 110°

Step-by-step explanation:

Let's recall that If the transversal cuts across parallel lines (apparently, this particular case) then those alternate exterior angles have the same measure (.∠ 110° and ∠?) So in the figure given, the two alternate exterior angles measure the same.

The missing angle measures also 110°

4 0

3 years ago

Please help! ive been stuck on this for so long and i just keep getting frustrated can someone help walkme through this?

bagirrra123 [75]

For firework launched from height 100ft with initial velocity 150ft/sec, equation made is correct

(a) equation will be $h(t) = -16t^2+150t+100$

(b) Now we have to see when it will land. At land or ground level height h will be equal to 0. So simply plug 0 in h place in equation made in part (a)

$0 = -16t^2 + 150t + 100$

Now we have to solve this quadratic. We will use quadratic formula method to solve this equation.

$t = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

a = -16, b = 150, c = 100.

Plugging these values in quadratic formula we get

$t = \frac{-150 \pm \sqrt{150^2-4(-16)(100)}}{2(-16)}$

$t = \frac{-150 \pm \sqrt{22500+6400}}{-32}$

$t = \frac{-150 \pm \sqrt{28900}}{-32}$

$t = \frac{-150+170}{-32} = \frac{20}{-32} = -0.625$

time cannot be negative so we will drop this answer

then $t = \frac{-150-170}{-32} = \frac{-320}{-32} = 10$

So 10 seconds is the answer for this

(c) To make table simply plug various value for t like t =0, 2, 4, 6, 8 till 10. Plug values in equation mad in part (a) and find h value for each t as shown

For t =0 seconds, $h = -16(0)^2+150(0)+100 = 100 feet$

For t =2 seconds, $h = -16(2)^2+150(2)+100 =336 feet$

For t =4 seconds, $h = -16(4)^2+150(4)+100 = 444 feet$

For t =6 seconds, $h = -16(6)^2+150(6)+100 = 424 feet$

For t =8 seconds, $h = -16(8)^2+150(8)+100 = 276 feet$

For t =10 seconds, $h = -16(10)^2+150(10)+100 = 0 feet$

(d) Axis of symmetry is given by formula

$x = \frac{-b}{2a}$

$t = \frac{-150}{2(-16)} =\frac{-150}{-32} = 4.6875$

t = 4.6875 is axis of symmetry line

(e) x-coordinate of vertex is again given by formula

$x = \frac{-b}{2a}$

so t = 4.6875

then to find y coordinate we will plug this value of t as 4.6875 in equation made in part (a)

For t =4.6875, $h = -16(4.6875)^2+150(4.6875)+100 = 451.563$

so vertex is at (4.6875, 451.563)

(f) As the firework is launched so in starting time is t=0, we cannot have time before t=0 (negative values) practically. Also we cannnot have firework going down into the ground so we cannot have h value negative physically.

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2 years ago