3 years ago

I need helppppp please

Mathematics

2 answers:

barxatty [35]3 years ago

7 0

It’s c I know the answer because I took the test

strojnjashka [21]3 years ago

4 0

C is the answer
Hope this helped

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natima [27]

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3 years ago

A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%

andre [41]

Answer: a) 683 b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

$p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}$

a) Given : Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}}=\pm1.96$

Margin of error : $E=0.03$

Formula to calculate the sample size needed for interval estimate of population proportion :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683$

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.03})^2=1067.11111111\approx1067$

Hence, the required sample size would be 1067 .

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3 years ago

18 ≥ 6x what is the answer

dangina [55]

Answer:

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Step-by-step explanation:

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2 years ago

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Factor completely m^7n+64mn^2

Serga [27]

Factor completely m^7n+64mn^2

mn(m^6+64n)

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