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2 years ago

1/secA-tanA - 1 /secA+tanA So the answer comes 2tanA/sec^2 A-tan^2A how ??.

Mathematics

1 answer:

solniwko [45]2 years ago

7 0

Answer:

Hope it helps

thanks ।।।।।।।।।।।।।

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58 = –2(m + 4) + m –22 –50 –66 –33

Anika [276]

Assignment: $\bold{Solve \ Equation: \ 58=-2\left(m+4\right)+m}$

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Answer: $\boxed{\bold{m=-66}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Switch Sides

$\bold{-2\left(m+4\right)+m=58}$

[ Step Two ] Expand $\bold{-2\left(m+4\right)+m}$

$\bold{-m-8}$

[ Step Three ] Rewrite Equation

$\bold{-m-8=58}$

[ Step Four ] Add 8 To Both Sides

$\bold{-m-8+8=58+8}$

[ Step Five ] Simplify

$\bold{-m=66}$

[ Step Six ] Divide Both Sides By -1

$\bold{\frac{-m}{-1}=\frac{66}{-1}}$

[ Step Seven ] Simplify

$\bold{x=-66}$

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$\bold{\rightarrow Mordancy \leftarrow}$

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2 years ago

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Help please explain in detail

yaroslaw [1]

Answer:

1. (n + 3)(5n + 8)

2. (x - 4)(7x - 4)

3. (k + 8)(7k + 1)

Step-by-step explanation:

1. We have to factorize 5n² + 23n + 24.

Now, 5n² + 23n + 24

= 5n² + 15n + 8n + 24

= 5n (n + 3) + 8 (n + 3)

=(n + 3)(5n + 8) (Answer)

2. We have to factorize 7x² - 32x + 16

Now, 7x² - 32x + 16

= 7x² - 28x - 4x + 16

= 7x (x - 4) - 4 (x - 4)

= (x - 4)(7x - 4) (Answer)

3. We have to factorize 7k² + 57k + 8

Now, 7k² + 57k + 8

= 7k² + 56k + k + 8

= 7k (k + 8) + 1 (k + 8)

= (k + 8)(7k + 1) (Answer)

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2 years ago

1/secA-tanA - 1 /secA+tanA So the answer comes 2tanA/sec^2 A-tan^2A how ??.​

1/secA-tanA - 1 /secA+tanA So the answer comes 2tanA/sec^2 A-tan^2A how ??.