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3 years ago

1/secA-tanA - 1 /secA+tanA So the answer comes 2tanA/sec^2 A-tan^2A how ??.

Mathematics

1 answer:

solniwko [45]3 years ago

7 0

Answer:

Hope it helps

thanks ।।।।।।।।।।।।।

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Find the Inverse of 3x^3-1=y

Anika [276]

$y = 3x^{3} - 1$
$x = 3y^{3} - 1$
$3y^{3} = x + 1$
$y^{3} = \frac{x + 1}{3}$

$y = \sqrt[3]{\frac{x + 1}{3}}$

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3 years ago

PLEASE HELP, WILL GIVE MAX POINTS IF CORRECT. Look at the diagram of the tennis court below. The diagram contains examples of li

zvonat [6]

Answer:

playing surface=plane

corner of serving box=vertex

baseline=line segment

net=plane

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Step-by-step explanation:

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3 years ago

Can anyone solve this? If so tell me and make sure u know what ur doing please

raketka [301]

Answer:

-2

Step-by-step explanation:

To find the slope of a line, you need to find the $\frac{rise}{run}$ between two points. I will be using the points (-3, 2) and (-1, -2).

$\frac{rise}{run}$ = $\frac{-2-2}{-1-(-3)}$

= $\frac{-2-2}{-1+3}$

= $\frac{-4}{2}$

= -2

6 0

3 years ago

Which radical expression in the picture is equivalent to t^5/8?

mixas84 [53]

<h3>Answer: Choice B</h3>

=========================================================

Explanation:

The rule we use is

$\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m$

where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).

So for instance,

$\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3$

or in this case,

$\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5$

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3 years ago

How do you increase 300 by 54%?

Vanyuwa [196]

Multiply 300 by 54%= 16,200
Divide 16,200 by 100
= 162.20
Round 162.20 to the nearest whole
= 162
hope this helps.
This is the steps to finding a percent

4 0

3 years ago

1/secA-tanA - 1 /secA+tanA So the answer comes 2tanA/sec^2 A-tan^2A how ??.​

1/secA-tanA - 1 /secA+tanA So the answer comes 2tanA/sec^2 A-tan^2A how ??.