Answer: the graph that passes through 0,1
Step-by-step explanation:
y=1/5x+1
IDK if i have to explain again but
A. (-infinity, infinity)
B. (-infinity, -3]
C. (-infinity, -4)u(-4, 0)u(0, infinity)
those u's are the logic symbol
2. domain: [-6, -1)u(-1, 3]u [3, -infinity)
range: (-infinity, 4]
3a. 8x^2 + 17
3b. 32x^2 + 80x + 53
3c. I cant see the multiplication symbol
9^1/3 * 3^x = 27^4/5
Rewrite 9 as 3^2
(3^2)^1/3 * 3^x = 27^4/5
Multiply the exponents in the first term:
3^2/3 * 3^x = 27^4/5
Use power rule to combine exponents:
3^(2/3 +x) = 27^4/5
Rewrite the 2nd term:
3^(2/3 +x) = (3^3)^4/5
Set the exponents only to equal:
2/3 + x = 3(4/5)
Solve for x:
simplify the right side:
2/3 + x = 12/5
Subtract 2/3 from both sides:
x = 26/15
8x + 4y = 20
4y = 20 - 8x
y = 5 - 2x
