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Ivan
3 years ago
8

A spinner with 20 equal-sized sections has 5 red, 10 blue, 3 green, and 2 yellow sections. Ann pays $10 to spin the spinner. If

she spins a yellow, she wins $20; if she spins green, she wins $15; otherwise, she loses.She plays the game twice. What is the expected payoff for her games?
Mathematics
1 answer:
zhenek [66]3 years ago
6 0

Answer:

The expected payoff for Ann is that she loses the game

Step-by-step explanation:

The expected payoff for Ann is that she loses the game, this is because only 5 out of the 20 sections allow Ann to win money, this is only 25% of the spinner. Meaning that 75% of the spinner will cause Ann to lose the game. Rolling two times increases the odds that she will lose the game. Since the greatest probability is that Ann will land on a section that causes her to lose the game, then this is the expected payoff.

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Read 2 more answers
AD←→ is tangent to circle M at point D. The measure of ∠DMQ is 58º.
Marat540 [252]

Answer:

32°

Step-by-step explanation:

Given:

∠DMQ = 58º

In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°

Therefore, ∠MDQ = 90°

The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:

180 = ∠DMQ + ∠MDQ + ∠DQM

Solving for ∠DQM, we have:

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∠DQM = 32°

The measure of ∠DQM is 32°

6 0
3 years ago
Write the definition of a function printarray, which has two parameters . the first parameter is an array of integers and the se
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Using pseudocode:

printArray(arr[], integers)
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7 0
3 years ago
Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

4 0
3 years ago
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