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stich3 [128]
3 years ago
7

Solve for g: 3g - 5 = 16 0 5 7 8 giving brainiest

Mathematics
2 answers:
dolphi86 [110]3 years ago
5 0

Answer:

g=7

Step-by-step explanation:

3g - 5 = 16

1. Add 5 to each side

3g = 21

2. Divide both sides by 3

g=7

Oxana [17]3 years ago
3 0

Answer:

The answer to that question is 7

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Tell whether a triangle can have sides with lengths 3, 4, and 8.
Vadim26 [7]

Answer:

Yeah a triangle can have any measurements as long as it makes sense. Your not gonna put the mesurment 8 on the shortest side but the longest, and then the next longest will be 4, and then 3 as the shortest.

Step-by-step explanation:

You'd be lookin for a scalene triangle, Acute triangle, or obtuse triangle, (I'm not so sure about a right triangle, but you might be lookin at that too)

I hope this helps!!!!

3 0
3 years ago
In T-ball, the distance to each successive base is 50 feet. If the distance from home plate to the pitcher’s mound is 38 feet, h
JulijaS [17]

Answer:

<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>

Step-by-step explanation:

The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.

We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

50^{2} =38^{2}+x^{2}\\x^{2}=50^{2}-38^{2}\\x=\sqrt{2500-1444}\\ x=\sqrt{1056}\\ x \approx 32.5 \ ft

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.

Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

50^{2}=32.5^{2}+y^{2}\\y^{2}=50^{2}-32.5^{2}\\y=\sqrt{2500-1056.25}\\ y =\sqrt{1443} \approx 37.99

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.

<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>

8 0
3 years ago
23:
irina [24]

Answer:

(-\frac{3}{7}, 0) -- x intercept

(0,3) -- y intercept

Step-by-step explanation:

Given

y = 7x + 3

Required

Determine the x and y intercept

For x intercept.

Set y = 0

So, we have:

y = 7x + 3

0 = 7x + 3

Collect Like Terms

7x = -3

Make x the subject

x = -\frac{3}{7}

Hence, the x intercept is: (-\frac{3}{7}, 0)

For the y intercept;

Set x = 0

So, we have:

y = 7x + 3

y = 7*0 + 3

y = 0 + 3

y = 3

Hence, the y intercept is: (0,3)

8 0
3 years ago
Read 2 more answers
The annual health insurance premium for Ms Everett is $12,304. her employer pays 70% of the premium and deducts the remainder fr
Gekata [30.6K]
Answer: See each one below:

1) Since she is paying for 30% of the cost, we multiply it by 0.3. Then, since it is over the whole year, we divide it by 12.

12304 * 0.3 / 12 = 307.6 B

2)  First, we subtract the cost of the 50 deductible, then multiply the amound by 0.2 because he has to pay 20% of the balance.
1060 - 50 = 1010 x 0.2 = 202 A

3)  First, we find the total cost of the visits. Mattie has to pay for 40% so times it by 0.4. Then, don't forget to add in the cost of 12 co-pays of $15 each.
3660 * 0.4 = 1464 + 15(12) = 1664 B
7 0
3 years ago
Read 2 more answers
what is the slope-intercept form for a line that has a slope of -4/5 and passes through points (0,7)?
drek231 [11]

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{7})~\hspace{10em} slope = m\implies -\cfrac{4}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=-\cfrac{4}{5}(x-0) \\\\\\ y-7=-\cfrac{4}{5}x\implies y=-\cfrac{4}{5}x+7

4 0
3 years ago
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