Answer:
see explanation
Step-by-step explanation:
1
Given
2x² - 16 = 0 ( add 16 to both sides )
2x² = 16 ( divide both sides by 2 )
x² = 8 ( take the square root of both sides )
x = ± 
= ± 2
------------------------------------
2
Given
- 5x² + 9 = 0 ( subtract 9 from both sides )
- 5x² = - 9 ( divide both sides by - 5 )
x² = 
( take the square root of both sides )
x = ± 
= ± 
-----------------------------------------
3
Given
6x² - 15 = 27 ( add 15 to both sides )
6x² = 42 ( divide both sides by 6 )
x² = 7 ( take the square root of both sides )
x = ± 
Answer:
Solution given
Cos I=adjacent/hypotenuse=16/34
<u>8</u><u>/</u><u>1</u><u>7</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Well the equation for slope is
number 5
which means the slope is
We must solve for x. Let's simplify this equation by dividing both sides by 6:
|2x-14|=7, which is the same as 2|x-7|=7.
First, assume that x-7 is already positive, so that we don't need the absolute value operator. Then x-7=7/2. Adding 7 to both sides results in x = 21/2.
Next, find the other solution:
Assume that x-7 is negative. Then |x-7|=-(x-7). Then -(x-7) = 7,
and -x + 7 = 7. Thus, x = 0.
The solution set is {0, 21/2}.
