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Brrunno [24]
3 years ago
14

You will include code that will validate all user input. If the user inputs an invalid value, the program will respond with an e

rror message and will ask the user to input the data again (use a do / while loop). Invalid values include:
Computers and Technology
1 answer:
alukav5142 [94]3 years ago
8 0

Answer:

See explanation (Program written in C++)

Explanation:

The question is incomplete as the invalid values were not included in the question.

However, to make the sense of it, I'll answer your question using the following conditions.

1. Invalid values include: Numbers less than 0 (See comments for explanations)

#include <iostream>

using namespace std;

int main() {

//This line declares num (for user input)

int num;

//The following iteration keeps repeating itself until a number greater than 0 is entered using do while loop

do{

//This line prompts user for input

cout<<"Numbers greater than 0: ";

//This line gets input from the user

cin>>num;}

while(num<1);//This condition checks for valid user input

cout<<"You entered: "<<num; //This line prints out the user input

}

2. Invalid values include: Odd Numbers

I'll make use of the above code (in 1)

Start by replacing:

cout<<"Numbers greater than 0: ";

with

cout<<"Even Numbers: "; //This prompts user for even numbers

Replace

while(num<1);

with

while(num%2==1); //This checks if input is odd. If yes, the loop is repeated

3. Invalid values include: Even Numbers

I'll make use of the above code (in 1)

Start by replacing:

cout<<"Numbers greater than 0: ";

with

cout<<"Odd Numbers: "; //This prompts user for Odd numbers

Replace

while(num<1);

with

while(num%2==0); //This checks if input is even. If yes, the loop is repeated

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Answer:

#include <stdio.h>

int main()

{

float your_value1, your_value2, your_value3, your_value4, your_value5;

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I have used the function scanf_s instead of scanf simply because my compiler does not work with scanf.

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