All categories

3 years ago

A ship sails 400km in 18hours.how many days will it take to cover 1600km at the same rate?

Mathematics

2 answers:

Nuetrik [128]3 years ago

5 0

Answer:

72 hours

Step-by-step explanation:

Rate =Distance / Time

Rate=400/18=22.222

Time=Distance/ Rate

Time= (1600 x 18)/400 = 72hours

VLD [36.1K]3 years ago

4 0

Answer:

3 days

Step-by-step explanation:

as it took 18 hours to complete 400 km and 1600 divide by 4 is four so we multiply 18 by four and get 72 which is 3 days

You might be interested in

What's the area of these?

kvasek [131]

Left side: 63, 72, 16 right side: 36, 4, 35

6 0

3 years ago

There are 120 Calories in a 34-cup serving of cereal. How many Calories are there in 6 cups of cereal? Enter your answer in the

Ilya [14]

Answer: 21.17 (22 rounded)

explanation: 120/34 = 3.529 calories per cup

3.529 x 6 cups = 21.17

hope this helps :)

7 0

2 years ago

Find the GCF. 14abc and 28a2b2c3

Zarrin [17]

The greatest common factor is the largest factor that both terms share.

First, start with the coefficients, 14 and 28. The largest factor they both share is 14. 14 x 1 = 14, 14 x 2 = 28.

Next we move to the variables, abc and a²b²c³. The largest factor the both share is abc, all to the power of 1.

So, your GCF and final answer is 14abc

5 0

2 years ago

Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini

Nat2105 [25]

By inspection, it's clear that the sequence must converge to $\dfrac32$ because

$\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32$

when $n$ is arbitrarily large.

Now, for the limit as $n\to\infty$ to be equal to $\dfrac32$ is to say that for any $\varepsilon>0$ , there exists some $N$ such that whenever $n>N$ , it follows that

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|$

From this inequality, we get

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}$
$\implies|2n-1|>\dfrac5{2\varepsilon}$
$\implies2n-1\dfrac5{2\varepsilon}$
$\implies n\dfrac12+\dfrac5{4\varepsilon}$

As we're considering $n\to\infty$ , we can omit the first inequality.

We can then see that choosing $N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil$ will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that $N\in\mathbb N$ .

6 0

2 years ago

Write 4 1/5 as a improper fraction

BartSMP [9]

Answer:

21/5

Step-by-step explanation:

8 0

2 years ago

A ship sails 400km in 18hours.how many days will it take to cover 1600km at the same rate?​

A ship sails 400km in 18hours.how many days will it take to cover 1600km at the same rate?