Y - y1 = m(x - x1)
slope(m) = -4/3
(0,-12)....x1 = 0 and y1 = -12
sub
y - (-12) = -4/3(x - 0) =
y + 12 = -4/3(x - 0) <=== point slope form
y + 12 = -4/3x
y = -4/3x - 12 <=== slope intercept form
y = -4/3x - 12
4/3x + y = -12
4x + 3y = -36 <=== standard form
Answer:
(16.5 + 1.5n)° = (12 + 2n)° [given]
=> 16.5 – 12 = 2n – 1.5n
=> 4.5 = 0.5n
=> n = 4.5/0.5
=> n = 9
1045 = 1000 since 45 is not near 2000
6589 = 7000
Near to low: 0, 1, 2, 3, 4
Nearer to High: 5, 6, 7, 8, 9
Answer:
The line is
.
Step-by-step explanation:
Given:
Point and slope (0,0) and 2/3.
Now, to determine the line.
Here the point is:
![(x_{1},y_{1}) =(0,0)](https://tex.z-dn.net/?f=%28x_%7B1%7D%2Cy_%7B1%7D%29%20%3D%280%2C0%29)
And the slope is:
![m=\frac{2}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B2%7D%7B3%7D)
Now, putting the formula and substituting the value from above to determine the line:
![y-y_{1} = m(x-x_{1})](https://tex.z-dn.net/?f=y-y_%7B1%7D%20%3D%20m%28x-x_%7B1%7D%29)
![y-0=\frac{2}{3}(x-0)](https://tex.z-dn.net/?f=y-0%3D%5Cfrac%7B2%7D%7B3%7D%28x-0%29)
![y=\frac{2}{3} x](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B3%7D%20x)
Therefore, the line is
.