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asambeis [7]
2 years ago
14

Please help me i'm begging you​

Mathematics
2 answers:
victus00 [196]2 years ago
5 0
5/6(3/2) = 15/12
5/4
1 and 1/4 hours
aev [14]2 years ago
3 0

Answer:

5/6(3/2) = 15/12

5/4

1 and 1/4 hours

I took the quiz

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If AABC = ADFE determine the values of x and y.
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8y - 5 = 99 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 8y = 99 + 5 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  8y = 104  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   y=  \frac{104}{8}   \\ \:  \:  \:  \ \:  \:  \:  y = 13

\:  \:  \:  \:  \:  \: 2y + x = 38.4 \\ 2(13) + x = 38.4 \\  \:  \:  \:  \:  \:  \: 26 + x = 38.4 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   x = 38.4 - 26 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  x = 12.4

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3 years ago
Which number is closest in value to the slope of line /?
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What's the picture?

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Y=3x+4 and crosses through the point (1,8)
erma4kov [3.2K]
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3 years ago
this table contains data on the number of people visiting a historical landmark over a period of one week. sketch a scatter plot
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6 0
3 years ago
on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solv
Cloud [144]
Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.


</span>
8 0
3 years ago
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