Answer:
36.5cm²
Step-by-step explanation:
Area of quarter circle=8²
/4=64
/4=16
cm²
Area of square+Area of shaded region =2(16
)=32
=100.5cm²
Area of square=8²=64cm²
Area of shaded region=100.5cm²-64cm²=36.5cm²
Therefore, the area of the shaded region is 36.5cm².
Answer:
Option (3). EF
Step-by-step explanation:
From the figure attached,
Plane defined by EAB can be represented by the face EABF of the square prism also.
Similarly, plane EFG can be represented by the face EFGH of the prism.
Now these sides EABF and EFGH are joining each other at the edge EF of the cuboid.
Therefore, intersection of the given planes is EF.
Option (3) will be the answer.
9514 1404 393
Answer:
zero solutions
Step-by-step explanation:
The first inequality has a boundary line with a slope of 3 and a y-intercept of 9. Shading is above the boundary line.
The second inequality has a parallel boundary line with a slope of 3 and a y-intercept somewhat lower, at -1. Shading is below this boundary line.
There is a gap between the shaded areas, so no points will be solutions to both inequalities.
Answer:
B. 13
Explanation:

Logarithm rules:

Breakdown of the expression:



insert given values


1a. 3^1 / 3^2 = 3^1-2 = 3^-1 = 1/3^1 = 1/3.
2b. 4^2 / 4^4 = 4^2-4 = 4^-2 = 1/4^2.
3c. 6^3/6^5 = 6^3-5 = 6^-2 = 1/6^2.
4d. 3^-5 • 3^2 = 3^-10 = 1/3^10.
I believe for the last question its asking only to rewrite exponent as a positive exponent similar to the first question.