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2 years ago

Which statement is true about this quadratic equation?

Mathematics

1 answer:

Masteriza [31]2 years ago

8 0

Answer:

There are two real roots because b²>4ac

in the equation, b²= 9² = 81.

4ac = 4×-4×-12= 72

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EASYY TO ANSWER I WILL MARK YOU AS BRILIANT HELP PLEASE

BARSIC [14]

Question 1: (0,2) because b value in mx+b is y-intercept

Question 2: plug in 4 for x you will get 1 so max is (4, 1)

Question 3: plug in -4 for x you will get -5 so min is (-4, -5)

Hope it helps :D

7 0

2 years ago

F(x)=x^2-9x+2 evaluate f(-2)

Anton [14]

I believe is your answer
Because u plug in -2 to all x
F(x)= (-2)^2-9(-2)+2
F(x)=4+18+2
F(x)=24

4 0

2 years ago

The mass of an electron is approximately 9 × 10-28 grams, while the mass of a neutron is approximately 2 × 10-24 grams. Which of

aalyn [17]

Answer: the mass of a neutron is approximately 2,000 times the mass of an electron

Step-by-step explanation:

- the easiest way to solve this (in my opinion) is to simply divide the mass of a neutron by the mass of an electron

- $2 x10^{-24} / (9 x10^{-28} )$

= $(2/9) x10^{-24--28}$

= $(2/9)x10^{-24+28}$

≈ $0.2222x10^{28-24}$

≈ $0.2222x10^{4}$

≈ which is approximately 2222

- so 2222 is approximately 2000 times

- therefore, the mass of a neutron is approximately 2,000 times the mass of an electron

hope this helps :)

4 0

1 year ago

Read 2 more answers

Your grandparents invested $2,000 for you on the day you were born. How much will this investment be worth on your 25th birthday

algol [13]

We know that, Amount in Compound interest is given by :

$\bigstar \ \ \boxed{\sf{Amount = Principal\bigg(1 + \dfrac{Rate \ of \ Interest}{100}\bigg)^{Time \ Period}}}$

Given : Principal = $2000

Given : Annual yield is 5% and the interest is compounded quarterly

It means : Interest is compounded 4 times in a year

$\implies \sf{Rate \ of \ Interest = \dfrac{R}{4} = \dfrac{5}{4}}$

$\sf{\implies Time \ period = (25 \times 4) = 100}$

Substituting all the values in the formula, we get :

$\implies \sf{Amount = 2000\bigg(1 + \dfrac{\dfrac{5}{4}}{100}\bigg)^{100}}$

$\implies \sf{Amount = 2000\bigg(1 + \dfrac{5}{400}\bigg)^{100}}$

$\implies \sf{Amount = 2000\bigg(1 + \dfrac{1}{80}\bigg)^{100}}$

$\implies \sf{Amount = 2000\bigg(\dfrac{81}{80}\bigg)^{100}}$

$\implies \sf{Amount = 2000 \times (1.0125)^{100}}$

$\implies \sf{Amount = 2000 \times 3.463}}$

$\implies \sf{Amount = 6926.8}$

8 0

2 years ago

Pls help I will mark

tatiyna

Answer:

Step-by-step explanation:

3 0

2 years ago